Answer:
3.5 cm
Explanation:
mass, m = 50 kg
diameter = 1 mm
radius, r = half of diameter = 0.5 mm = 0.5 x 10^-3 m
L = 11.2 m
Y = 2 x 10^11 Pa
Area of crossection of wire = π r² = 3.14 x 0.5 x 10^-3 x 0.5 x 10^-3
= 7.85 x 10^-7 m^2
Let the wire is stretch by ΔL.
The formula for Young's modulus is given by


ΔL = 0.035 m = 3.5 cm
Thus, the length of the wire stretch by 3.5 cm.
Answer:
a. The total momentum of the trolleys which are at rest before the separation is zero
b. The total momentum of the trolleys after separation is zero
c. The momentum of the 2 kg trolley after separation is 12 kg·m/s
d. The momentum of the 3 kg trolley is -12 kg·m/s
e. The velocity of the 3 kg trolley = -4 m/s
Explanation:
a. The total momentum of the trolleys which are at rest before the separation is zero
b. By the principle of the conservation of linear momentum, the total momentum of the trolleys after separation = The total momentum of the trolleys before separation = 0
c. The momentum of the 2 kg trolley after separation = Mass × Velocity = 2 kg × 6 m/s = 12 kg·m/s
d. Given that the total momentum of the trolleys after separation is zero, the momentum of the 3 kg trolley is equal and opposite to the momentum of the 2 kg trolley = -12 kg·m/s
e. The momentum of the 3 kg trolley = Mass of the 3 kg Trolley × Velocity of the 3 kg trolley
∴ The momentum of the 3 kg trolley = 3 kg × Velocity of the 3 kg trolley = -12 kg·m/s
The velocity of the 3 kg trolley = -12 kg·m/s/(3 kg) = -4 m/s
Answer:
First Question

Second Question
The wavelength is for an X-ray
Explanation:
From the question we are told that
The width of the wall is 
The first excited state is
The ground state is 
Gnerally the energy (in MeV) of the photon emitted when the proton undergoes a transition is mathematically represented as
![E = \frac{h^2 }{ 8 * m * l^2 [ n_1^2 - n_0 ^2 ] }](https://tex.z-dn.net/?f=E%20%20%20%3D%20%20%20%5Cfrac%7Bh%5E2%20%7D%7B%208%20%2A%20m%20%20%2A%20%20l%5E2%20%5B%20n_1%5E2%20-%20n_0%20%5E2%20%5D%20%7D)
Here h is the Planck's constant with value 
m is the mass of proton with value 
So
![E = \frac{( 6.626*10^{-34})^2 }{ 8 * (1.67 *10^{-27}) * (10 *10^{-15})^2 [ 2^2 - 1 ^2 ] }](https://tex.z-dn.net/?f=E%20%20%3D%20%20%20%5Cfrac%7B%28%206.626%2A10%5E%7B-34%7D%29%5E2%20%7D%7B%208%20%2A%20%281.67%20%2A10%5E%7B-27%7D%29%20%20%2A%20%20%2810%20%2A10%5E%7B-15%7D%29%5E2%20%5B%202%5E2%20-%201%20%5E2%20%5D%20%7D)
=> 
Generally the energy of the photon emitted is also mathematically represented as

=> 
=> 
=> 
Generally the range of wavelength of X-ray is 
So this wavelength is for an X-ray.