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Pavlova-9 [17]
2 years ago
7

To start the analysis of this circuit you must write energy conservation (loop) equations. Each equation must involve a round-tr

ip path that begins and ends at the same location. Each segment of the path should go through a wire, a bulb, or a battery (not through the air). How many valid energy conservation (loop) equations is it possible to write for this circuit?

Physics
1 answer:
REY [17]2 years ago
6 0

Answer:

Explanation:

Electric field talks about a region around a charged particle or object within which a force would be exerted on other charged particles or objects. to find the electric field inside the bulb we will apply the electric filed formula.

Please kindly check attachment for step by step explaination.

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Two parallel plates are a distance apart with a potential difference between them. a point charge moves from the negatively char
Ghella [55]

Answer:

We can relate the kinetic energy of the particle to the potential difference between the plates by following equations:

Work energy theorem:

W_{total} = \Delta K = K_2 - K_1 = w - 0

W = Fx\\F = W/d = w/d

F = Eq \\E = F/q = w/(dq)

V = Ed = \frac{w}{dq} d = w/q

So,

w = Vq

If the distance is doubled and the potential difference is halved, then

w = qV/2

Explanation:

As can be seen from the relationship between kinetic energy and the potential difference, the distance between the plates has no effect on the relation between kinetic energy and the potential difference. Since the charge of the second particle is equal to that of the first one, the new kinetic energy would be half of the first kinetic energy.

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2 years ago
As an object in motion becomes heavier, its kinetic energy _____. A. increases exponentially B. decreases exponentially C. incre
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Answer:

USE SOCRACTIC IT WOULD REALLY HELP

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2 years ago
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The position function x(t) of a particle moving along an x axis is x = 4.00 - 6.00t2, with x in meters and t in seconds. (a) at
elena-14-01-66 [18.8K]

The position function x(t) of a particle moving along an x axis is x=4.00 - 6.00t^2

a) The point at which particle stop, it's velocity = 0 m/s

  So dx/dt = 0

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  So when time t= 0, velocity = 0 m/s

    So the particle is starting from rest.

At t = 0 the particle is (momentarily) stop

b) When t = 0

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SO at x = 4m the particle is (momentarily) stop

c) We have x=4.00 - 6.00t^2

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  Substituting

         0 = 4.00 - 6.00t^2\\ \\ t^2 = \frac{2}{3}

         t = 0.816 seconds or t = - 0.816 seconds

So when  t = 0.816 seconds and t = - 0.816 seconds, particle pass through the origin.

5 0
2 years ago
Pamela drove her car 999999 kilometers and used 999 liters of fuel. she wants to know how many kilometers (k)(k)left parenthesis
Vanyuwa [196]
When the relationship between two variables are said to be proportional, it means that one variable is a constant multiple of the other variable. They are related by a constant of proportionality, usually denoted as k. 

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By variation,

distance,1/liters of fuel,1 = distance,2/liters of fuel,2, where 1 denotes situation 1 and 2 denotes situation 2. Therefore,

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x = (999999*121212)/999
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The acceleration is0.25m/s^2
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