To determine the distance in units of feet of the object falling at a given time, we simply use the relation given above and substitute the given value of time to the function. We do as follows:
s = 16t^2
s = 16 ( 6 )^2
s = 576 feet
The distance of the object from the ground at 6 seconds is 576 ft.
The correct option is d)greater input distance and a smaller force
Why?
We must remember that while a pulley has more rope sections, the force requiered to lift the load will be smaller, but the input distance required to lift the load will be greater.
Hence, for the problem, the correct option is d)greater input distance and a smaller force.
Have a nice day!
As we know that
here we know that
now from above equation we have
so image will form on left side of lens at a distance of 15 cm
This image will be magnified and virtual image
Ray diagram is attached below here
The heavy stone would produce waves with a higher amplitude, rather than the smaller stone, because since the stone is heaver its going to have a grater impact and displace more water to create a bigger wave.
Answer:
<h2>
The potential difference increases </h2>
Explanation:
from the relation 
where E= electric field (force per coulomb)
V= voltage
d= distance
Hence the voltage is going to be V= E×d.
Therefore this means that increasing the distance increases the voltage.
