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leva [86]
2 years ago
5

A battery charges a parallel-plate capacitor fully and then is removed. The plates are then slowly pulled apart. What happens to

the potential difference between the plates as they are being separated?
Physics
1 answer:
White raven [17]2 years ago
3 0

Answer:

<h2>The potential difference increases </h2>

Explanation:

from the relation E= \frac{V}{d}

where E= electric field (force per coulomb)

            V= voltage

            d= distance

Hence the voltage is going to be V= E×d.

Therefore this means that increasing the distance increases the voltage.

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A damped harmonic oscillator consists of a block of mass 2.5 kg attached to a spring with spring constant 10 N/m to which is app
Cerrena [4.2K]

Answer:

0.5% per oscillation

Explanation:

The term 'damped oscillation' means an oscillation that fades away with time. For Example; a swinging pendulum.

Kinetic energy, KE= 1/2×mv^2-------------------------------------------------------------------------------------------------------------(1).

Where m= Mass, v= velocity.

Also, Elastic potential energy,PE=1/2×kX^2----------------------------------------------------------------------------------------------------------------------(2).

Where k= force constant, X= displacement.

Mechanical energy= potential energy (when a damped oscillator reaches maximum displacement).

Therefore, we use equation (3) to get the resonance frequency,

W^2= k/m--------------------------------------------------------------------------------------(3)

Slotting values into equation (3).

= 10/2.5.

= ✓4.

= 2 s^-1.

Recall that, F= -kX

F^2= (-0.1)^2

Potential energy,PE= 1/2 ×0.01

Potential energy= 0.05 ×100

= 0.5% per oscillation.

6 0
2 years ago
At its lowest setting a centrifuge rotates with an angular speed of ω1 = 250 rad/s. When it is switched to the next higher setti
dalvyx [7]

Answer:

Part(a): The angular acceleration is 5.63~rad~s^{-2}.

Part(b): The angular displacement is 2629~rad.

Explanation:

Part(a):

If \omega_{1},~\omega_{2}~and~\alpha be the initial angular speed, final angular speed and angular acceleration  of the centrifuge respectively, then from rotational kinematic equation, we can write

\alpha = \dfrac{\omega_{2} - \omega_{1}}{t}......................................................(I)

where 't' is the time taken by the centrifuge to increase its angular speed.

Given, \omega_{i} = 250~rad~s^{-1}, \omega_{f} = 750~rad~s^{-1} and t = 9.5~s. From equation (I), the angular acceleration is given by

\alpha = \dfrac{750 - 250}{9.5}~rad~s^{-2} = 5.63~rad~s^{-2}

Part(b):

Also the angular displacement (\Delta \theta) can be written as

&&\Delta \theta = \omega_{1}~t + \dfrac{1}{2}\alpha~t^{2}\\&or,& \Delta \theta = (250 \times 9.5 + \dfrac{1}{2} \times 5.63 \times 9.5^{2})~rad = 2629~rad

8 0
2 years ago
Marissa researched the cost to have custom T-shirts printed by several local and online vendors. She found that each store’s cha
myrzilka [38]
I’m slightly confused about the wording of the question but if both the same y-intercept that means both company’s have the same flat rate charge for artwork.
8 0
2 years ago
Read 2 more answers
Babylonians obtained wood for building from
yanalaym [24]

Answer: t-trees?

i couldn't find anything on this topic but the only thing i could think of was trees, maybe if you go to a history website you can find a answer there :)

hope i helped a little :)

6 0
2 years ago
A radioactive source has a half life of 80s.
Burka [1]
Lets make the original number of nuclides at the start is 100.

If 7/8 of 100 is decayed, that means 87.5 decayed.

\frac{7}{8} \times 100 = 87.5

And there is 1/8 left of the number of nuclide 100. Which is 12.5

100 - 87.5 =12.5

\frac{1}{8} \times 100 = 12.5

How many Half lifes passed for 100 to become 12.5 is 3 Half-Lives.

100 \div 2 \div 2 \div 2 = 12.5

Each Half-Life is 80 seconds so there is 240 seconds

3 \times 80 = 240The answer is that it takes 240 seconds.
6 0
2 years ago
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