Answer: The same current flows through bth cables
Explanation:
Lets have a look to the next two equations
The Ohm´s V = I*R (1)
where:
V is voltage (potencial dfference) in volts
I is the electric current in ampers
R is the electric resistance
When a voltage is applied as the electrc load is not specified ( we have to assume is the same) the current will be the same
And in the other hand the resistance R =ρL/s
Where ρ is the resistivity of the conductor L the length and s square section of the conductor
If we assume that the smaller diameter cable is able to conduct the current then nothing happens. The point is that the capacity of conduction of current depend on the section of the cable (the area)
Tables exist where to find the capacity of each cable according to its diameter.
Given that,
Distance in south-west direction = 250 km
Projected angle to east = 60°
East component = ?
since,
cos ∅ = base/hypotenuse
base= hyp * cos ∅
East component = 250 * cos 60°
East component = 125 km
Answer:
Frequency will be equal to 5.20 kHz
So option (c) will be correct answer
Explanation:
We have given value of capacitance 
Potential difference across capacitor V = 12 volt
Current through capacitor 
Capacitive reactance will be equal to 
Capacitive reactance is equal to 




f = 5.20 kHz
So frequency will be equal to 5.20 kHz
So option (c) will be correct answer
We know that acceleration is change in velocity by time taken for that change.
In this case velocity change is 3.7 m/s
Time taken for this change = 60 ms = 
So acceleration of frog = 
= 61.66 m/
So acceleration of frog is 61.66 m/
o it is evident that frog is capable of remarkable accelerations.
F is the focal length of the lens. A positive f indicates a converging optical device, like a convex lens or a concave mirror.
Choice A