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arlik [135]
2 years ago
12

A new technology company is marketing drones for residential use. The bar graph shows the relation between number of sales and t

hree types of marketing strategies over the company’s first five months of operation. What are the two biggest advantages of using a bar graph to display this kind of data? The graph provides a comparison of the different marketing strategies. The graph helps in selecting the best marketing strategy to improve sales. The graph helps to predict future sales near the end of the calendar year. The graph indicates how many people see the posted advertisements. The graph gives information about the number of people who have received emails.
Physics
1 answer:
NARA [144]2 years ago
4 0

Answer:

<em><u>1- The graph provides a comparison of the different marketing strategies</u></em>

<em><u /></em>

<em><u>2- The graph helps in selecting the best marketing strategy to improve sales</u></em>

Explanation:

Hope this help

plz mark brainliest

Have a nice day!!!

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g A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobb
Law Incorporation [45]

Answer:

Explanation:

total weight acting downwards

= 3g + 10g

13 g

volume of lead = 10 / 11.3 = .885 cm³

Let the volume of bobber submerged in water be v in floating position . buoyant force on bobber  = v x 1 x g

Buoyant force on lead =  .885 x 1 x g

total buoyant force = vg + .885 g

For floating

vg + .885 g  = 13 g

v = 12.115 cm³

total volume of bobber

= 4/3 x 3.14 x 2³

= 33.5 cm³

fraction of volume submerged

= 12.115  / 33.5

= .36  

= 36 %

4 0
2 years ago
An 800-N billboard worker stands on a 4.0-m scaffold weighing 500 N and supported by vertical ropes at each end. How far would t
Lynna [10]

Answer:

2.5 m

Explanation:

Weight of billboard worker = 800 N

Number of ropes = 2

Length of scaffold = 4 m

Weight of scaffold = 500 N

Tension in rope = 550 N

The sum of the torques will be

-800(4-x)-500\times 2+550\times 4=0\\\Rightarrow -800(4-x)=500\times 2-550\times 4\\\Rightarrow -800(4-x)=-1200\\\Rightarrow -x=\dfrac{1200}{800}-4\\\Rightarrow -x=-2.5\\\Rightarrow x=2.5\ m

The position of the person will be 2.5 m

7 0
2 years ago
A bicycle tire rotates 25 times in 10 seconds. What is it’s average angular velocity?
ryzh [129]
<h2>Answer:</h2>

<u>Angular velocity of bicycle tire is 15.78 radians per second.</u>

<h3>Explanation:</h3>

Angular velocity is the change in angular speed of an object with respect to time take for change or it is the rate of change of circular motion.

In the given question the circular displacement is 25 rounds around a central point.

The angular displacement is measured in degrees and 1 round is equal to 360 degrees.

25 Rounds = 25 × 360 = 9000 degrees.

Angular velocity = angular displacement /time = 9000/10 = 900 degrees per second.

In SI,angular velocity is represented in radians per second.

So, 1 radian = 57.29 degrees

Angular velocity = 15.78 radians per second

3 0
2 years ago
Two chargedparticles, with charges q1=q and q2=4q, are located at a distance d= 2.00cm apart on the x axis. A third charged part
erica [24]

Answer:

Two possible points

<em>x= 0.67 cm to the right of q1</em>

<em>x= 2 cm to the left of q1</em>

Explanation:

<u>Electrostatic Forces</u>

If two point charges q1 and q2 are at a distance d, there is an electrostatic force between them with magnitude

\displaystyle f=k\frac{q_1\ q_2}{d^2}

We need to place a charge q3 someplace between q1 and q2 so the net force on it is zero, thus the force from 1 to 3 (F13) equals to the force from 2 to 3 (F23). The charge q3 is assumed to be placed at a distance x to the right of q1, and (2 cm - x) to the left of q2. Let's compute both forces recalling that q1=1, q2=4q and q3=q.

\displaystyle F_{13}=k\frac{q_1\ q_3}{d_{13}^2}

\displaystyle F_{13}=k\frac{(q)\ (q)}{x^2}

\displaystyle F_{23}=k\frac{q_2\ q_3}{d_{23}^2}

\displaystyle F_{23}=k\frac{(q)(4q)}{(0.02-x)^2}

\displaystyle F_{23}=\frac{4k\ q^2}{(0.02-x)^2}

Equating

\displaystyle F_{13}=F_{23}

\displaystyle \frac{K\ q^2}{x^2}=\frac{4K\ q^2}{(0.02-x)^2}

Operating and simplifying

\displaystyle (0.02-x)^2=4x^2

To solve for x, we must take square roots in boths sides of the equation. It's very important to recall the square root has two possible signs, because it will lead us to 2 possible answer to the problem.

\displaystyle 0.02-x=\pm 2x

Assuming the positive sign :

\displaystyle 0.02-x= 2x

\displaystyle 3x=0.02

\displaystyle x=0.00667\ m

x=0.67\ cm

Since x is positive, the charge q3 has zero net force between charges q1 and q2. Now, we set the square root as negative

\displaystyle 0.02-x=-2x

\displaystyle x=-0.02\ m

\displaystyle x=-2\ cm

The negative sign of x means q3 is located to the left of q1 (assumed in the origin).

5 0
2 years ago
Choose which statements correctly identify the relationship of mass volume and density by clicking the sentence
stealth61 [152]
Mass is the amount of matter present in an object, it also determines the strength of the mutual gravitational force of an object to another object. Volume is the amount of space that the object occupies. Meanwhile, density is the amount of mass per volume of an object, with that formula, we can say that density is directly proportional to the mass but indirectly proportional to the volume.
7 0
2 years ago
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