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blondinia [14]
2 years ago
15

A certain signal molecule S in heart tissue is degraded by two different biochemical pathways: when only Path 1 is active, the h

alf-life of S is 3.9 s. When only Path 2 is active, the half-life of S is 104. s. Calculate the half-life of S when both pathways are active.
Physics
1 answer:
Misha Larkins [42]2 years ago
6 0

Answer:

Half life of S = 3.76secs

Explanation:

The concept of half life in radioactivity is applied. Half life is the time taken for a radioactive material to decay to half of its initial size.

For part 1 - How much signal will be degraded in 1secs = 1/3.9 = 0.2564

for part 2 - How much signal will be degraded in 1secs = 1/104 = 0.009615

Simply say = 1/3.9 + 1/104 = 0.266015

So both part 1 and part 2 took 1/0.266015 = 3.76secs is the half life of S when both pathways are active

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A dog is chasing a cat towards a tree. The cat has a 10-yard lead and runs at 6 yards per second. The dog runs at a speed of 8 y
oksano4ka [1.4K]

Answer : Cat will reach tree first.

Explanation :

It is given that,

Total distance between dog and tree is 30 yards. The cat has 10 yards lead. So, the distance between cat and tree is 20 yards.

Speed of cat  is 6 Yards/ sec.

Speed of dog is 8 Yards/sec.

speed of cat is, S_c=\dfrac{distance\ covered\ by\ cat}{time\ taken}

6\ Yards/sec=\dfrac{20\ Yards}{t_c}

t_c=3.33\ sec

Now, speed of dog is, S_d=\dfrac{distance\ covered\ by\ dog}{time\ taken}

8\ Yards/sec=\dfrac{30\ yards}{t_d \ sec}

t_d=3.75\ sec

It is clear that, cat is taking less time as compared with dog. So, the cat will reach tree first.

3 0
2 years ago
Explain why it is dangerous to jump from a fast moving train
Sergeu [11.5K]

Answer:

When you jump off a train, you jump off a certain height and your downwards (vertical) velocity is zero. But your forward (horizontal) velocity is not. You will hit the ground on split second with your horizontal velocity practically the same as the train.

Explanation:

you be in serious injury.

7 0
2 years ago
The number that is used to show the value of one currency compared to another is called the __________. A. trade rate B. currenc
Brrunno [24]

Answer:

c is the answer

Explanation:

8 0
2 years ago
Block A, mass 250 g , sits on top of block B, mass 2.0 kg . The coefficients of static and kinetic friction between blocks A and
masha68 [24]

Answer:

  F = 69.3 N

Explanation:

For this exercise we use Newton's second law, remembering that the static friction force increases up to a maximum value given by

               fr = μ N

We define a reference system parallel to the floor

block B  ( lower)

Y axis  

            N - W₁-W₂ = 0

            N = W₂ + W₂

            N = (M + m) g

X axis

              F -fr = M a

for block A (upper)

X axis

              fr = m a                 (2)

so that the blocks do not slide, the acceleration in both must be the same.

Let's solve the system by adding the two equations

             F = (M + m) a          (3)

             a =\frac{F}{ M+m}

the friction force has the formula

            fr = μ N

             fr = μ (M + m) g

let's calculate

            fr = 0.34 (2.0 + 0.250) 9.8

            fr = 7.7 N

we substitute in equation 2

             fr = m a

             a = fr / m

             a = 7.7 / 0.250

             a = 30.8 m / s²

we substitute in equation 3

             F = (2.0 + 0.250) 30.8

             F = 69.3 N

5 0
2 years ago
A planar loop consisting of seven turns of wire, each of which encloses 200 cm2, is oriented perpendicularly to a magnetic field
PtichkaEL [24]

Answer:

The induced current is 0.084 A

Explanation:

the area given by the exercise is

A = 200 cm^2 = 200x10^-4 m^2

R = 5 Ω

N = 7 turns

The formula of the emf induced according to Faraday's law is equal to:

ε = (-N * dφ)/dt = (N*(b2-b1)*A)/dt

Replacing values:

ε = (7*(38 - 14) * (200x10^-4))/8x10^-3 = 0.42 V

the induced current is equal to:

I = ε /R = 0.42/5 = 0.084 A

3 0
2 years ago
Read 2 more answers
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