Answer: 9938.8 km
Explanation:
1 pound-force = 4.48 N
30.0 pounds-force = 134.4 N
The force of gravitation between Earth and object on the surface of is given by:

Where M is the mass of the Earth, m is the mass of the object, R (6371 km) is the radius of the Earth.
At height, h above the surface of the Earth, the weight of the object:

we need to find "h"
taking the ratio of two:

Hence, Pete would weigh 30 pounds at 9938.8 km above the surface of the Earth.
The work done is the product between the intensity of the force applied F, the amount of the displacement d of the book and the cosine of the angle

between the direction of the force and the direction of the displacement:

In our problem, the student is lifting the book, so he is applying a force directed upward, and the book is moving upward, so F and d are parallel and therefore the angle is zero, so

Therefore, the work done is
Answer:
7.9 
Explanation:
Take the fact that mass is inversely proportional to accelertation:
m ∝ a
Therefore m = a, but because we are finding the change in acceleration, we would set our problem up to look more like this:

Using algebra, we can rearrange our equation to find the final acceleration,
:

Before plugging everything in, since you are being asked to find acceleration, you will want to convert 0.85g to m/s^2. To do this, multiply by g, which is equal to 9.8 m/s^2:
0.85g * 9.8
= 8.33
Plug everything in:
7.9
= 
(1590kg the initial weight plus the weight of the added passenger)
Find Displacement and Distance
displacement ...
north is 700+400+100 =1200m n
south=1200m
1200-1200=0
east is 300+300=600m
west is 600m
600-600=0
back at dtart. displ zero
distance is 700+ 300m + 400 m + 600m + 1200m + 300m + 100m = 3600m
Answer:
The time constant and its uncertainty is t ± Δt = 0.526 ± 0.057 s
Explanation:
If we make a comparison we have to:
y = A*(1-e^-(C*x)) + B
If the time remains constant we have to:
t = R*C = 1/C
In this way we calculate the time constant and its uncertainty. this will be equal to:
t ± Δt = (1/1.901) ± (0.2051/1.901)*(1/1.901) = 0.526 ± 0.057 s