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cestrela7 [59]
2 years ago
7

A ramp 20 m long and 4 m high is used to lift a heavy box. A pulley system with 4 rope sections supporting the load is used to l

ift an identical box to a height of 4 m. If friction is ignored, the ramp requires a _____ to lift the load.
a)greater input distance and a greater force

b)smaller input distance and a greater force

c)smaller input distance and a smaller force

d)greater input distance and a smaller force
Physics
1 answer:
irga5000 [103]2 years ago
8 0

The correct option is d)greater input distance and a smaller force

Why?

We must remember that while a pulley has more rope sections, the force requiered to lift the load will be smaller, but the input distance required to lift the load will be greater.

Hence, for the problem, the correct option is d)greater input distance and a smaller force.

Have a nice day!

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An 80 kg skateboarder moving at 3 m/s pushes off with her back foot to move faster. If her velocity increases to 5 m/s, what is
Arturiano [62]
1) The kinetic energy of an object is given by:
K= \frac{1}{2}mv^2
where m is the object's mass and v its speed.

By using this equation, we find the initial kinetic energy of the skateboarder:
K_i= \frac{1}{2}(80 kg)(3 m/s)^2=360 J
and the final kinetic energy as well:
K_f= \frac{1}{2}(80 kg)(5 m/s)^2=1000 J

So, her change in kinetic energy is
\Delta K=K_f-K_i=1000 J-360 J=640 J

2) The work-energy theorem states that the work done to increase the speed of an object is equal to the variation of kinetic energy of the object:
W=\Delta K
Therefore, the work done by the skateboarder is
W=\Delta K=640 J
7 0
2 years ago
Read 2 more answers
How many calories are equal to one BTU? (One calorie = 4.186 J, one BTU = 1 054 J.)
I am Lyosha [343]
<h2>Option C is the correct answer.</h2>

Explanation:

We need to find how many calories is 1 BTU.

Given

          1 BTU = 1054 J

          1 calorie = 4.186 J

So we have

          1 BTU = 4.186 x 251.79 J

          1 BTU =251.79 calorie

          1 BTU = 252 calorie.

Option C is the correct answer.

3 0
2 years ago
On an amusement park ride, passengers are seated in a horizontal circle of radius 7.5 m. The seats begin from rest and are unifo
timofeeve [1]

Answer:

a = 0.5 m/s²

Explanation:

Applying the definition of angular acceleration, as the rate of change of the angular acceleration, and as the seats begin from rest, we can get the value of the angular acceleration, as follows:

ωf = ω₀ + α*t

⇒ ωf = α*t ⇒ α = \frac{wf}{t} = \frac{1.4 rad/s}{21 s} = 0.067 rad/s2

The angular velocity, and the linear speed, are related by the following expression:

v = ω*r

Applying the definition of linear acceleration (tangential acceleration in this case) and angular acceleration, we can find a similar relationship between the tangential and angular acceleration, as follows:

a = α*r⇒ a = 0.067 rad/sec²*7.5 m = 0.5 m/s²

3 0
2 years ago
At a certain instant after jumping from the airplane A, a skydiver B is in the position shown and has reached a terminal (consta
Lubov Fominskaja [6]

Answer:

a=2330

b= 0.223secs

Explanation:

pb=2330m

t=0.223secs

6 0
2 years ago
A machine has an efficiency of 20 percent. Find the input work if the output work is 140 Joules
Lapatulllka [165]

Answer:

X= 700 Joules

Explanation:

The question asked about the efficiency of the work done.

The formula for efficiency is: Efficiency = (Useful output / input work) * 100%

The useful output given in the question is 140J, the question asked for input work. Let X be the input work. It is also given that the efficiency is 20%.

Using the formula of efficiency,

20 = (140/X) * 100

So, we simply solve the above equation.

X= 140*100/20

X= 700 Joules

6 0
2 years ago
Read 2 more answers
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