All categories

1 year ago

A machine has an efficiency of 20 percent. Find the input work if the output work is 140 Joules

Physics

2 answers:

Lapatulllka [165]1 year ago

6 0

Answer:

X= 700 Joules

Explanation:

The question asked about the efficiency of the work done.

The formula for efficiency is: Efficiency = (Useful output / input work) * 100%

The useful output given in the question is 140J, the question asked for input work. Let X be the input work. It is also given that the efficiency is 20%.

Using the formula of efficiency,

20 = (140/X) * 100

So, we simply solve the above equation.

X= 140*100/20

X= 700 Joules

vazorg [7]1 year ago

4 0

Answer:

The input work = 700 Joules

Explanation:

Given Data:

Efficiency = 20%

Output work = 140 joules

Input work = ?

The input work done can be calculated using the efficiency formula;

Efficiency = output work done/input work done * 100

Substituting, we have

20 = 140/Input work * 100

20 = 14000/input work

20*input work = 14000

input work = 14000/20

= 700 joules

You might be interested in

The blade of metal cutter is shorter than that scissors of tailors<br><br>

Naily [24]

Explanation:it is beause they are sharper and also have less surface area and therefore more pressure

8 0

2 years ago

Find the net electric force that the two charges would exert on an electron placed at point on the xx-axis at xx = 0.200 mm. Exp

UkoKoshka [18]

Answer:

The question has some details missing, here is the complete question ; A -3.0 nC point charge is at the origin, and a second -5.0nC point charge is on the x-axis at x = 0.800 m. Find the net electric force that the two charges would exert on an electron placed at point on the x-axis at x = 0.200 m.

Explanation:

The application of coulonb's law is used to approach the question as shown in the attached file.

6 0

1 year ago

. Imagine that you are standing at the center of a giant bowl of gelatin. What type of wave will you make across the top of the

vichka [17]

Transverse wave as the wave is going up and down no compressions

3 0

2 years ago

Two long conducting cylindrical shells are coaxial and have radii of 20 mm and 80 mm. The electric potential of the inner conduc

xxMikexx [17]

Answer: 14.52*10^6 m/s

Explanation: In order to explain this problem we have to consider the energy conservation for the electron within the coaxial cylidrical wire.

the change in potential energy for the electron; e*ΔV is equal to energy kinetic gained for the electron so:

e*ΔV=1/2*m*v^2 v^=(2*e*ΔV/m)^1/2= (2*1.6*10^-19*600/9.1*10^-31)^1/2=14.52 *10^6 m/s

3 0

1 year ago

An unspecified force causes a 0.20-kg object to accelerate at 0.40 m/s2. If 0.30 kg is added to the 0.20-kg object and the force

Naddik [55]

Answer:

a = 0.16

Explanation:

given,

mass of the object 1 = 0.2 kg

mass of the object 2 = 0.3 kg

acceleration when force is on 0.2 kg = 0.4 m/s²

acceleration when both mass are combine = ?

F = m a

F = 0.2 × 0.4

F = 0.08 N

force acting is same and total mass = 0.2 + 0.3 = 0.5 Kg

F = m a

$a = \dfrac{F}{m}$

$a = \dfrac{0.08}{0.5}$

a = 0.16 m/s²

the acceleration acting when both the body is attached is a = 0.16

4 0

2 years ago