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1 year ago

14

Which of the following statements would be best described as an expression of an attitude that is low in accessibility and high

in ambivalence?
A.
Frank: “I eat a banana for breakfast everyday. I’ve loved them since I was little.”
B.
Judy: “I really dislike bananas. I don’t know why. I just always have.”
C.
Ralph: “I’m not sure about bananas. I’d have to think about it.”
D.
Fiona: “I am a huge banana fan. I don’t know why. I just like them.”

2 answers:

SpyIntel [72]1 year ago

7 0

Answer:

The answer is C. Ralph: “I’m not sure about bananas. I’d have to think about it.”

Explanation:

I did the practice.

Crazy boy [7]1 year ago

4 0

Answer:

C.

Ralph: “I’m not sure about bananas. I’d have to think about it.”

Explanation:

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A solenoid of length 0.700m having a circular cross-section of radius 5.00cm stores 6.00 μJ of energy when a 0.400-A current run

AURORKA [14]

Answer:

The winding density of the solenoid, n = 104 turns/m

Explanation:

Given that,

Length of the solenoid, l = 0.7 m

Radius of the circular cross section, r = 5 cm = 0.05 m

Energy stored in the solenoid, $E=6\ \mu J=6\times 10^{-6}\ J$

Current, I = 0.4 A

To find,

The winding density of the solenoid.

Solution,

The expression for the energy stored in the solenoid is given by :

$U=\dfrac{1}{2}LI^2$

Where

L is the self inductance of the solenoid

$L=\mu_on^2lA$

n is the winding density of the solenoid

$n=\sqrt{\dfrac{2U}{\mu_oI^2l\pi r^2}}$

$n=\sqrt{\dfrac{2\times 6\times 10^{-6}}{4\pi \times 10^{-7}\times 0.7\times (0.4)^2\pi (0.05)^2}}$

n = 104 turns/m

So, the winding density of the solenoid is 104 turns/m

8 0

1 year ago

Read 2 more answers

Water runs into a fountain, filling all the pipes, at a steady rate of 0.750 m3>s. (a) How fast will it shoot out of a hole 4

kati45 [8]

Answer:

velocity = 472 m/s

velocity = 52.4 m/s

Explanation:

given data

steady rate = 0.750 m³/s

diameter = 4.50 cm

solution

we use here flow rate formula that is

flow rate = Area × velocity .............1

0.750 = $\frac{\pi }{4}$ × (4.50× $10^{-2}$ )² × velocity

solve it we get

velocity = 472 m/s

and

when it 3 time diameter

put valuer in equation 1

0.750 = $\frac{\pi }{4}$ × 3 × (4.50× $10^{-2}$ )² × velocity

velocity = 52.4 m/s

5 0

1 year ago

Identify the row that contains two scalars and one vector quantity: Distance Acceleration Velocity Speed Mass Acceleration Dista

GenaCL600 [577]

Answer:

Speed, mass and acceleration

Explanation:

A scalar quantity is a quantity that has only magnitude but no direction while a vector quantity has both magnitude and direction.

According to the question, the row that has two scalars and one vector is speed, mass and acceleration.

The two scalars in this row are speed and mass while the vector quantity there is the acceleration.

Acceleration has direction since it possess direction. A body accelerating will do so in a particular direction. Speed and mass doesn't possess any direction. Mass only specify the magnitude of the body but no clue as to which direction is the body moving towards.

Speed also only specify the

total distance covered with respect to time but not the direction of the direction.

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1 year ago

You've always wondered about the acceleration of the elevators in the 101 story-tall Empire State Building. One day, while visit

love history [14]

To develop this problem we will proceed to convert all units previously given to the international system for which we have to:

$140 lb = 63.5 kg \rightarrow 63.5kg (9.8m/s) =622.3 N$

$120 lb = 54.4 kg \rightarrow 54.4kg (9.8m/s)= 533 N$

$170 lb = 77.1 kg \rightarrow 77.1 kg (9.8m/s) =756 N$

PART A ) From the given values the minimum acceleration will be given for 120Lb and maximum acceleration when 170Lb is reached therefore:

$F = 756 - 622.3$

$F = 133.7N$

Through the Newtonian relationship of the Force we have to:

$F= ma$

$a = \frac{F}{m}$

$a = \frac{133.7}{63.5}$

$a = 2.1m/s^2$

PART B) For the maximum magnitude of the acceleration downward we have that:

$F = 622.3 - 533$

$F = 89.3N$

Through the Newtonian relationship of the Force we have to:

$F= ma$

$a = \frac{F}{m}$

$a = \frac{89.3}{63.5}$

$a = 2.1m/s^2$

$a = 1.04 m/s^2$

7 0

2 years ago

A ball of mass 0.4 kg is initially at rest on the ground. It is kicked and leaves the kicker's foot with a speed of 5.0 m/s in a

yawa3891 [41]

Answer:

the answer the correct is 3

Explanation:

Let's use the relationship between momentum and momentum

I = Δp

I = m $v_{f}$ - m v₀

Let's calculate

I = 0.4 5.0 - 0

I = 2.0 N s

By Newton's law of action and reaction the force on the ball is equal to the force that the ball exerts on the foot, therefore the impulse on the foot of equal magnitude, but in the opposite direction

I = 2.0 Ns with 60°

When reviewing the answer the correct is 3

4 0

2 years ago