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m_a_m_a [10]
2 years ago
13

Some fuel cells are powered by hydrogen. Scientists are looking into the decomposition of water (H2O) to make hydrogen fuel with

the help of the Sun’s energy. What challenge do scientists face with this task?
A.

Decomposing water requires a high activation energy.

B.

The Sun isn't a renewable resource.

C.

Decomposing water results in toxic byproducts.

D.

Scientists are uncertain what to do with the excess oxygen.
Physics
2 answers:
Sauron [17]2 years ago
6 0

Answer:

A. Decomposing water requires a high activation energy.

Explanation:

The leftovers of the division of the molecule of water would be Hydrogen that would be used as fuel, and oxygen which is necessary and its benefical for humans, so there would be no toxical residuals, and the residuals could be thrown to the air, so the most challenging thing that the scientist would face would be the fact that the molecule of water has a really strong bond between the oxygen and the two atoms of hydrogen, so it requires a really high activation energy.

mr_godi [17]2 years ago
5 0

A challenge scientists face with this process is the use of ultrathin iron oxide, to pull protons off water and produce hydrogen gas, which itself is a poor electrical conductor.

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A 100 cm3 block of lead weighs 11N is carefully submerged in water. One cm3 of water weighs 0.0098 N.
Pie

#1

Volume of lead = 100 cm^3

density of lead = 11.34 g/cm^3

mass of the lead piece = density * volume

m = 100 * 11.34 = 1134 g

m = 1.134 kg

so its weight in air will be given as

W = mg = 1.134* 9.8 = 11.11 N

now the buoyant force on the lead is given by

F_B = W - F_{net}

F_B = 11.11 - 11 = 0.11 N

now as we know that

F_B = \rho V g

0.11 = 1000* V * 9.8

so by solving it we got

V = 11.22 cm^3

(ii) this volume of water will weigh same as the buoyant force so it is 0.11 N

(iii) Buoyant force = 0.11 N

(iv)since the density of lead block is more than density of water so it will sink inside the water


#2

buoyant force on the lead block is balancing the weight of it

F_B = W

\rho V g = W

13* 10^3 * V * 9.8 = 11.11

V = 87.2 cm^3

(ii) So this volume of mercury will weigh same as buoyant force and since block is floating here inside mercury so it is same as its weight =  11.11 N

(iii) Buoyant force = 11.11 N

(iv) since the density of lead is less than the density of mercury so it will float inside mercury


#3

Yes, if object density is less than the density of liquid then it will float otherwise it will sink inside the liquid

3 0
2 years ago
A car moving with constant acceleration covers the distance between two points 60 m apart in 6.0 s. Its speed as it passes the s
BlackZzzverrR [31]

Answer:

The speed in the first point is: 4.98m/s

The acceleration is: 1.67m/s^2

The prior distance from the first point is: 7.42m

Explanation:

For part a and b:

We have a system with two equations and two variables.

We have these data:

X = distance = 60m

t = time = 6.0s

Sf = Final speed = 15m/s

And We need to find:

So = Inicial speed

a = aceleration

We are going to use these equation:

Sf^2=So^2+(2*a*x)

Sf=So+(a*t)

We are going to put our data:

(15m/s)^2=So^2+(2*a*60m)

15m/s=So+(a*6s)

With these equation, you can decide a method for solve. In this case, We are going to use an egualiazation method.

\sqrt{(15m/s)^2-(2*a*60m)}=So

15m/s-(a*6s)=So

\sqrt{(15m/s)^2-(2*a*60m)}=15m/s-(a*6s)

[\sqrt{(15m/s)^2-(2*a*60m)}]^{2}=[15m/s-(a*6s)]^{2}

(15m/s)^2-(2*a*60m)}=(15m/s)^{2}-2*(a*6s)*(15m/s)+(a*6s)^{2}

-120m*a=-180m*a+36s^{2}*a^{2}

0=120m*a-180m*a+36s^{2}*a^{2}

0=-60m*a+36s^{2}*a^{2}

0=(-60m+36s^{2}*a)*a

0=a1

\frac{60m}{36s^{2}} = a2

1.67m/s^{2}=a2

If we analyze the situation, we need to have an aceleretarion  greater than cero. We are going to choose a = 1.67m/s^2

After, we are going to determine the speed in the first point:

Sf=So+(a*t)

15m/s=So+1.67m/s^2*6s

15m/s-(1.67m/s^2*6s)=So

4.98m/s=So

For part c:

We are going to use:

Sf^2=So^2+(2*a*x)

(4.98m/s)^2=0^2+(2*(1.67m/s^2)*x)

\frac{24.80m^2/s^2}{3.34m/s^2}=x

7.42m=x

5 0
2 years ago
Springfield's "classic rock" radio station broadcasts at a frequency of 102.1 mhz. what is the length of the radio wave in meter
Mila [183]
The frequency of the radio wave is:
f=102.1 MHz = 102.1 \cdot 10^6 Hz

The wavelength of an electromagnetic wave is related to its frequency by the relationship
\lambda= \frac{c}{f}
where c is the speed of light and f the frequency. Plugging numbers into the equation, we find
\lambda= \frac{3 \cdot 10^8 m/s}{102.1 \cdot 10^6 Hz}= 2.94 m
and this is the wavelength of the radio waves in the problem.
7 0
2 years ago
A boy uses a slingshot to launch a pebble straight up into the air. The pebble reaches a height of 37.0 m above the launch point
denis-greek [22]

Answer:

V0=27.4 m/s; t=0.8 s

Explanation:

Final position y=37.0 m, time = 2.3 s; Initial position is set to be zero. We calculate the initial speed with the kinematics equation:

y_f=v_0t-0.5*g*t^2 We solve for initial speed

v_0=\frac{y_f+0.5gt^2}{t}=\frac{37+4.9*2.3^2}{2.3}=27.4m/s

Now, using the same expression we estimated time to first reach 18.5 m :

18.5=27.4t-4.9t^2 Second order equation with solutions

t1=0.8 s and t2=4.8 s

The first time corresponds to the first reach.

7 0
2 years ago
Water evaporates off lakes. Winds blow across the planet. Where does the energy come from for these and other weather processes?
Otrada [13]

Answer:

B. Solar energy

Explanation:

The water cycle is driven primarily by the energy from the sun. This solar energy drives the cycle by evaporating water from the oceans, lakes, rivers, and even the soil. Other water moves from plants to the atmosphere through the process of transpiration.

8 0
2 years ago
Read 2 more answers
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