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2 years ago

The natural direction of heat flow between two reservoirs depends on ....

Physics

1 answer:

valentina_108 [34]2 years ago

8 0

Answer:

a. their temperatures

Explanation:

Hello.

In this case, among the options:

a. their temperatures .

b. their internal energy contents .

c. their pressures .

d. whether they are in the solid, liquid, or gaseous state.

We must remember that the driving force assisting heat transfer is the temperature difference which states that the heat flows from higher temperatures to lower temperatures based on the second law of thermodynamics. Therefore answer is a. their temperatures .

Best regards.

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olganol [36]

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$R = \rho \frac{L}{A} = (1.72 \times 10^{-8} \Omega m)\frac{1.5 \times 10^{-3} m}{3.14 \times 10^{-4} m^2} = 8.21 \times 10^{-8} \Omega$

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2 years ago

What is the approximate pressure of a storage cylinder of recovered r-410a that does not contain any non-condensable impurities

Aliun [14]

Answer:

173psig

Explanation:

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2 years ago

Before you start taking measurements though, we’ll first make sure you understand the underlying concepts involved. By what meth

Svetradugi [14.3K]

Answer:

If they are metallic spheres they are connected to earth and a charged body approaches

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Explanation:

For fillers, there are two fundamental methods, depending on the type of material.

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2 years ago

A block of mass m1 = 3.5 kg moves with velocity v1 = 6.3 m/s on a frictionless surface. it collides with block of mass m2 = 1.7

maxonik [38]

First, let's find the speed $v_i$ of the two blocks m1 and m2 sticked together after the collision.
We can use the conservation of momentum to solve this part. Initially, block 2 is stationary, so only block 1 has momentum different from zero, and it is:
$p_i = m_1 v_1$
After the collision, the two blocks stick together and so now they have mass $m_1 +m_2$ and they are moving with speed $v_i$ :
$p_f = (m_1 + m_2)v_i$
For conservation of momentum
$p_i=p_f$
So we can write
$m_1 v_1 = (m_1 +m_2)v_i$
From which we find
$v_i = \frac{m_1 v_1}{m_1+m_2}= \frac{(3.5 kg)(6.3 m/s)}{3.5 kg+1.7 kg}=4.2 m/s$

The two blocks enter the rough path with this velocity, then they are decelerated because of the frictional force $\mu (m_1+m_2)g$ . The work done by the frictional force to stop the two blocks is
$\mu (m_1+m_2)g d$
where d is the distance covered by the two blocks before stopping.
The initial kinetic energy of the two blocks together, just before entering the rough path, is
$\frac{1}{2} (m_1+m_2)v_i^2$
When the two blocks stop, all this kinetic energy is lost, because their velocity becomes zero; for the work-energy theorem, the loss in kinetic energy must be equal to the work done by the frictional force:
$\frac{1}{2} (m_1+m_2)v_i^2 =\mu (m_1+m_2)g d$
From which we can find the value of the coefficient of kinetic friction:
$\mu = \frac{v_i^2}{2gd}= \frac{(4.2 m/s)^2}{2(9.81 m/s^2)(1.85 m)}=0.49$

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2 years ago

Alex goes cruising on his dirt bike. He rides 700m north, 300m east, 400 m north, 600m west, 1200m south, 300m east and finally

Bess [88]

Find Displacement and Distance

displacement ...

north is 700+400+100 =1200m n

south=1200m

1200-1200=0

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west is 600m

600-600=0

back at dtart. displ zero

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2 years ago

The natural direction of heat flow between two reservoirs depends on ....​

The natural direction of heat flow between two reservoirs depends on ....