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seraphim [82]
1 year ago
13

Cass is walking her dog (Oreo) around the neighborhood. Upon arriving at Calina's house (a friend of Oreo's), Oreo turns part mu

le and refuses to continue on the walk. Cass yanks on the chain with a 67 N force at an angle of 30° above the horizontal. Determine the horizontal and vertical components of the tension force.
Physics
1 answer:
MArishka [77]1 year ago
4 0

Answer:

Horizontal component: F_x = 58\ N

Vertical component: F_y = 33.5\ N

Explanation:

To find the horizontal and vertical components of the force, we just need to multiply the magnitude of the force by the cosine and sine of the angle with the horizontal, respectively.

Therefore, for the horizontal component, we have:

F_x = F * cos(angle)

F_x = 67 * cos(30)

F_x = 58\ N

For the vertical component, we have:

F_y = F * sin(angle)

F_y = 67 * sin(30)

F_y = 33.5\ N

So the horizontal component of the tension force is 58 N and the vertical component is 33.5 N.

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Answer:

a_c=9.66\frac{m}{s^2}

Explanation:

The centripetal acceleration is given by:

a_c=\frac{v^2}{r}(1)

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v=\frac{2\pi r}{T}(2)

Replacing (2) in (1) and replacing the given values:

a_c=\frac{(\frac{2\pi r}{T})^2}{r}\\a_c=\frac{4\pi^2 r}{T^2}\\a_c=\frac{4\pi^2 (1.85m)}{(2.75s)^2}\\a_c=9.66\frac{m}{s^2}

7 0
1 year ago
Find the mass of a person walking west at a speed of 0.8 m/s with a momentum of 52.0 kg.m/s west.
KIM [24]

Answer:

mass of the person walking to west is 65 kg.

Given:

Momentum = 52 \frac{kg m}{s}

Speed = 0.8 \frac{m}{s}

To find:

Mass of the person = ?

Formula used:

Momentum is given by,

P = m × v

Where, P = momentum

m = mass

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Solution:

Momentum is given by,

P = m × v

Where, P = momentum

m = mass

v = speed

Mass = \frac{P}{v}

m = \frac{52}{0.8}

m = 65 kg

Thus, mass of the person walking to west is 65 kg.

5 0
1 year ago
The curved section of a horizontal highway is a circular unbanked arc of radius 740m. If the coefficient of static friction betw
fiasKO [112]
Coefficient of static friction = tan(a) = 0.4
r = 740 m
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v \:  =  \:  \sqrt{gr \tan( \alpha ) }
v = √(9.8 × 740 × 0.4) m/s
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Answer:

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Answer: D

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