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2 years ago

Which of these properties of an object best quantifies its inertia: velocity, acceleration, volume, mass, or temperature?

Physics

1 answer:

LuckyWell [14K]2 years ago

3 0

Answer:

Mass

Explanation:

Inertia is essentially an object's tendency to stay in motion or at rest unless it is forced to do otherwise (pun intended). It only makes sense to me that mass would best quantify an object's inertia, because an object with more mass would be harder to move and/or stop from moving.

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A boy does 465 J of work pulling an empty wagon along level ground with a force of 111 N [31o below the horizontal]. A frictiona

vovikov84 [41]

Can you list the answer's

6 0

1 year ago

The following represents a process used to assemble a chair with an upholstered seat. stationsa, b, and c make the seat; station

Mekhanik [1.2K]

There are three questions here:

A. The possible daily output of this process if there is 8 processing time each day?

the time it takes to assemble a chair in seconds = A + B + C + J + K + L + X + Y + Z

which is equal to = 38 + 34 + 35 + 32 + 30 + 34 + 22 + 18 + 20 =263 per chair

Processing hours = 8 hours x 60 minutes x 60 seconds

= 8 x 60 x 60

= 480 x 60 = 28,800 seconds is available in an 8 hr day.

28,800 / 263 =109.5057034220532

Therefore, It is possible to make 109 chairs in an 8 hour day.

B. Given your output rate in above, what is the efficiency of the process?

The time it takes to assemble a chair in seconds = A+ B + C + J + K + L + X + Y + Z.

= 34 + 34 + 34 + 30 + 30 + 30 + 22 + 18 + 20 = 252.6315789473684 per chair

A total of 252 per chair

Processing hours = 8 hours x 60 minutes x 60 seconds

= 8 x 60 x 60

= 480 x 60 = 28,800 seconds is available in an 8 hour day

= 28,000 / 252 = 114.2857142857143114 chairs

= 109/114 x 100 = 95.6140350877193

Therefore, the efficiency of making the chair is 95.61%

C. What is the flow time of the process?

Flow time is the period that it takes a completed chair to flow through the process from the beginning assemblage step to the last step. Take note that ABC and JKL are parallel legs in the process, and as a result both do not include to flow time to the procedure. In addition, Flow time comprises both pass time and run time at each position in the procedure.

7 0

2 years ago

If you are driving 72 km/h along a straight road and you look to the side for 4.0 s, how far do you travel during this inattenti

Ann [662]

We know that speed equals distance between time. Therefore to find the distance we have that d = V * t. Substituting the values d = (72 Km / h) * (1h / 3600s) * (4.0 s) = 0.08Km.Therefore during this inattentive period traveled a distance of 0.08Km

8 0

2 years ago

An object begins at position x = 0 and moves one-dimensionally along the x-axis witļi a velocity v

Liula [17]

Answer:

The answer is "between 20 s and 30 s".

Explanation:

Calculating the value of positive displacement:

$\ (x_{+ve}) = \frac{1}{2} \times 15 \times 20 \\\\$

$= \frac{1}{2} \times 300 \\\\= 150 \\\\$

Calculating the value of negative displacement upon the time t:

$(x_{-ve}) = \frac{1}{2} \times 5 \times 20- 20(t-20) \\\\$

$= \frac{1}{2} \times 100- 20t+ 400 \\\\= 50- 20t+ 400 \\\\$

$\to X= X_{+ve} + X_{-ve} \\\\$

$\to 150 - 50 -20t+400 =0\\\\\to 100 -20t+400 =0 \\\\\to 500 -20t =0\\\\\to 20t =500 \\\\\to t=\frac{500}{20}\\\\\to t=\frac{50}{2}\\\\\to t= 25$

That's why its value lie in "between 20 s and 30 s".

6 0

2 years ago

Now that we have a feel for the state of the circuit in its steady state, let us obtain the expression for the current in the ci

vesna_86 [32]

Answer:

i(t) = (E/R)[1 - exp(-Rt/L)]

Explanation:

E−vR−vL=0

E− iR− Ldi/dt = 0

E− iR = Ldi/dt

Separating te variables,

dt/L = di/(E - iR)

Let x = E - iR, so dx = -Rdi and di = -dx/R substituting for x and di we have

dt/L = -dx/Rx

-Rdt/L = dx/x

interating both sides, we have

∫-Rdt/L = ∫dx/x

-Rt/L + C = ㏑x

x = exp(-Rt/L + C)

x = exp(-Rt/L)exp(C) A = exp(C) we have

x = Aexp(-Rt/L) Substituting x = E - iR we have

E - iR = Aexp(-Rt/L) when t = 0, i(0) = 0. So

E - i(0)R = Aexp(-R×0/L)

E - 0 = Aexp(0) = A × 1

E = A

So,

E - i(t)R = Eexp(-Rt/L)

i(t)R = E - Eexp(-Rt/L)

i(t)R = E(1 - exp(-Rt/L))

i(t) = (E/R)(1 - exp(-Rt/L))

5 0

2 years ago