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2 years ago

9

In the Roman soldier model for refraction, what happens to the first soldier who hits the muddy stream?.....HELP PLZ.... A. They

slow down and turn slightly B. They slow down and keep going straight C. They speed up and keep going straight D. They speed up and turn slightly

1 answer:

SpyIntel [72]2 years ago

7 0

Answer:

uKkskdjod 7q and the rays are the best in all the ways ❤ ♥

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For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo

Snezhnost [94]

Answer:

114.86%

Explanation:

In both cases, there is a vertical force equal to the sprinter's weight:

Fy = mg

When running in a circle, there is an additional centripetal force:

Fx = mv²/r

The net force is found with Pythagorean theorem:

F² = Fx² + Fy²

F² = (mv²/r)² + (mg)²

F² = m² ((v²/r)² + g²)

F = m √((v²/r)² + g²)

Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

5 0

1 year ago

In 2016 there were 2025 reported collisions between trains and cars that’s resulted in 265 fatalities. Explain the change in kin

Law Incorporation [45]

Answer B

Explanation:

7 0

1 year ago

An application of this principle is that a line mounted on transparent slide casts the same diffraction pattern as a dark film w

kifflom [539]

Explanation:

It is given that,

The distance between the first spot and the central minimum is, s = 0.007 cm

Length, l = 12 m

Wavelength, $\lambda=6\times 10^{-7}\ m$

We need to find the width of the hair. Using the condition of diffraction pattern as :

$s=\dfrac{m\lambda l}{d}$ , d is the width of the hair

$d=\dfrac{m\lambda l}{s}$

$d=\dfrac{1\times 6\times 10^{-7}\times 12}{0.007}$

d = 0.00102

or

$d=1.02\times 10^{-3}\ m$

So, the width of the hair is $1.02\times 10^{-3}\ m$ . Hence, this is the required solution.

8 0

2 years ago

What is the instantaneous velocity of a freely falling object 9.0 s after it is released from a position of rest? Express your a

Umnica [9.8K]

Answer:

So instantaneous velocity after 9 sec will be 88.2 m/sec

Explanation:

We have given time t = 9 sec

As the object is released from rest so its initial velocity u = 0 m/sec

We have to find its final velocity v

Acceleration due to gravity $g=9.8m/sec^2$

From first equation of motion we know that $v=u+gt$

$v=0+9.8\times 9=88.2m/sec$

So instantaneous velocity after 9 sec will be 88.2 m/sec

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2 years ago

A device used to increase or decrease the emf in the second of two unconnected coils is a

grigory [225]

<span>The answer is transformer. They utilize electromagnetic induction to generate current. This is only possible in alternating current due to the differential increase and decrease of electrical current that induces changes in magnetic flux in the coil. This varies the magnetic flux of the primary coil that generates current in the secondary coil.</span>

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2 years ago