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joja [24]
1 year ago
8

A blue puck has a velocity of 0i – 3j m/s and a mass of 4 kg. A gold puck has a velocity of 12i – 5j m/s and a mass of 6 kg. Wha

t is the kinetic energy of the system?
Physics
1 answer:
Mnenie [13.5K]1 year ago
6 0
By definition, the kinetic energy is given by:
 K = (1/2) * m * v ^ 2
 where
 m = mass
 v = speed
 We must then find the speed of both objects:
 blue puck
 v = root ((0) ^ 2 + (- 3) ^ 2) = 3
 gold puck
 v = root ((12) ^ 2 + (- 5) ^ 2) = 13
 Then, the kinetic energy of the system will be:
 K = (1/2) * m1 * v1 ^ 2 + (1/2) * m2 * v2 ^ 2
 K = (1/2) * (4) * (3 ^ 2) + (1/2) * (6) * (13 ^ 2)
 K = <span> 525</span> J
 answer
 The kinetic energy of the system is<span> <span>525 </span></span>J
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An astronaut takes what he measures to be a 10-min nap in a space station orbiting Earth at 8000 m/s. A signal is sent from the
svet-max [94.6K]

Answer:

longer than

Explanation:

given,

time of nap = 10 min

speed of orbiting earth = 8000 m/s

c is the speed of light

using the equation of time dilation

t' = \dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}}}

now inserting all the values

t' = \dfrac{10}{\sqrt{1-\dfrac{8000^2}{3\times 10^8)^2}}}

t' = \dfrac{10}{0.9999}

t' = 10.001 s

on solving the above equation we will get a value greater than 10minutes.

hence, On earth time of nap measured will be longer than 10 min

3 0
2 years ago
You will now use Graphical Analysis to calculate the slope of the line. Choose Analyze from the menu. Select Automatic Curve Fit
Vlad1618 [11]
The value for the slope is <span>M=1.13</span>
3 0
1 year ago
An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large o
8_murik_8 [283]

Answer:

The gplanet is 0.193 m/s^2

Explanation:

The speed of the pulse is:

v=\frac{lengthofthewipe}{traveltime} =\frac{1.6}{0.0656} =15.24m/s

v=\sqrt{\frac{MgL}{m} } \\v^{2} =\frac{MgL}{m} \\g=\frac{mv^{2} }{ML}

where

m=mass of the wire=4 g= 4x10^-3 kg

M=mass of the object= 3 kg

Replacing values:

g=\frac{4x10^{-3}*15.24^{2}  }{3*1.6} =0.193 m/s^{2}

7 0
2 years ago
At what height h above the ground does the projectile have a speed of 0.5v?
maw [93]

Answer:

h=\dfrac{3v^2}{8g}

Explanation:

It is given that,

Speed of the projectile is 0.5 v. Let h is the height above the ground. Using the first equation of motion to find it.

v=u+at

v=u-gt

Initial speed of the projectile is v and final speed is 0.5 v.

0.5v=v-gt

t=\dfrac{v}{2g}

g is the acceleration due to gravity

Let h is the height above the ground. Using the second equation of motion as :

h=vt-\dfrac{1}{2}gt^2

h=v\dfrac{v}{2g}-\dfrac{1}{2}g(\dfrac{v}{2g})^2

h=\dfrac{3v^2}{8g}

So, the height of the projectile above the ground is \dfrac{3v^2}{8g}. Hence, this is the required solution.

6 0
1 year ago
When balancing an assembly line, which of the following is not a way to reduce the longest task time below the required workstat
tiny-mole [99]

Answer:

D. Speed up the assembly line transfer mechanism

Explanation:

All of the options are logic and very intelligent ways to reduce the longest task time, but if you just speed up the assembly line transfer you will end up with two possible outcomes, frustrated workers cause they always have to be rushing up to finish their task and thus a lower quality in the product you are producing, or that the workers on that specific part of the assembly line definetely can´t perform the task and endu up not doing their job and you end up with incomplete products.

6 0
2 years ago
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