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attashe74 [19]
2 years ago
13

A parallel-plate capacitor is constructed of two square plates, size L×L, separated by distance d. The plates are given charge ±

Q.
Part A
What is the ratio Ef/Ei of the final electric field strength Ef to the initial electric field strength Ei if Qis doubled?
Part BWhat is the ratio Ef/Ei of the final electric field strength Ef to the initial electric field strength Ei if Lis doubled?Part CWhat is the ratio Ef/Ei of the final electric field strength Ef to the initial electric field strength Ei if d is doubled?
Physics
1 answer:
vampirchik [111]2 years ago
3 0

Answer: A) 2 B) 4 C) 1

Explanation:

The Electric field from a parallel-plate capacitor  is given by:

A) E=Q/(L^2 * ε0) so if we put a charge double the final electric field is double that the original.

B) from the above expression for the electric field,  If the size of the plate is double, then the E final is four times weaker that the original.

C) If the distante between plates is doubled the final electric field is the same that initial.

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A ball is thrown with a velocity of 35 meters per second at an angle of 30° above the horizontal. which quantity has a magnitude
enot [183]
The quantity that has a magnitude of zero when the ball is at the highest point in its trajectory is the vertical velocity.

In fact, the motion of the ball consists of two separate motions:
- the horizontal motion, on the x-axis, which is a uniform motion with constant velocity v_x=v_0 cos 30^{\circ}, where v_0=35 m/s
- the vertical motion, on the y-axis, which is a uniformly accelerated motion with constant acceleration g=9.81 m/s^2 directed downwards, and with initial velocity v_y=v_= sin 30^{\circ}. Due to the presence of the acceleration g on the vertical direction (pointing in the opposite direction of the initial vertical velocity), the vertical velocity of the ball decreases as it goes higher, up to a point where it becomes zero and it reverses its direction: when the vertical velocity becomes zero, the ball has reached its maximum height. 
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2 years ago
The boom hoisting sheave must have pitch diameters of no less than _______times the nominal diameter of the rope used.
alexira [117]

Answer:

18 times

Explanation:

According to the security purposes which is set under the rules and regulation OSHA, which describes all the rights to the worker.

In the boom hoist receiving system all the sheaves which are used should have a pitch diameter of rope not less than 18 times the diameter of the nominal rope which is used.

7 0
2 years ago
in which sealed container would the organisms be able to continuously cycle o2 and co2 gases? a. a jar with a lizard eating a sn
DerKrebs [107]

Correct answer choice is :


C) A jar with snails crawling on living plants


Explanation:


By using the power of sunlight, plants can change carbon dioxide and water into glucose and oxygen in a method described photosynthesis. As photosynthesis needs sunlight, this method only occurs during the day. We usually like to think of this as plants `exhaling in carbon dioxide and `breathing out oxygen. Gas transfer between Alveolar Spaces and Capillaries. The role of the respiratory system is to transfer two gases, oxygen and carbon dioxide. The transfer takes place in the millions of alveoli in the lungs and the capillaries that surround them.


4 0
2 years ago
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What is the final temperature when a 3.0 kg gold bar at 99 0C is dropped into 0.22 kg of water at 25oC?
slavikrds [6]

I will post my work, but is that 99 degrees Celsius and 25 degrees Celsius?


All you have to do is plug in the initial temperature for gold where it says Tg and the initial temperature for the water where it says Tw and then plug that in and you will have your answer.

8 0
2 years ago
flat block is pulled along a horizontal flat surface by a horizontal rope perpendicular to one of the sides. The block measures
Lelu [443]

Answer:

Answered

Explanation:

v= 1 m/s

A= 1 m^2

m= 100 kg

y= 1 mm

μ = ?

ζ= viscosity of  SAE 20 crankcase oil of 15° C= 0.3075 N sec/m^2

forces acting on the block are  

                                 F_s   ←    ↓     →F_f

                                                mg

N= mg

F_s=  shear force = ζAv/y        F_f= friction force = μN

now in x- direction F_s= F_f

ζAv/y  =  μN

0.3075×1×1×1/1×10^{-3} = μ×100

⇒μ=0.313 (coefficient of sliding friction for the block)

Now, as the velocity is increased shear force also increases and due to this frictional force also increases.

Now, to compensate this frictional force friction coefficient must increase

as v∝μ

7 0
2 years ago
Read 2 more answers
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