A 5-kg concrete block is lowered with a downward acceleration of 2.8 m/s2 by means of a rope. The force of the block on the Eart
1 answer:
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Answer:
Option (c) will be correct answer that is it will go 1.6 m
Explanation:
We have given that conveyor has the velocity u = 3.1 m/sec
Mass of the robot = 10 kg
static friction coefficient = 0.5 and kinetic friction coefficient = 0.3
Acceleration due to gravity g = 9.8
Acceleration a = kinetic friction coefficient ×g = 0.3×9.8 = 2.94
Now according to third equation of motion
Finally velocity of the conveyor will be zero
So
s = 1.6 m
So option (c) is correct option
The man ran <u>4252.5 meters.</u>
Why?
To solve the problem, we need to divide the exercise into two movements, the first on while the was running at 4.5 m/s for 15 min, and then, while he was slowing down (going up because of the hill).
First movement: Running at 4.5 m/s for 15 min.
We need convert from minutes to seconds,
Now, calculating the distance covered for the first movement, we have:
So, we know that the man covered 4050m for the first movement, it will be our initial position for the second movement.
Second movement: acceleration -0.05m/s^2 (because he's slowing down) for 90 seconds, at 4.5m/s.
Hence, we have that he ran 4252.5 m.
Have a nice day!