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marusya05 [52]
2 years ago
11

After observing a moth that is camouflaged against dark-colored bark, a scientist asks a question. The scientist discovers that

the question has already been asked and answered by several investigations. What should the scientist do?The scientist should test the question anyway.
The scientist should broaden the scope of the question.
The scientist should come up with a new way to test the question.
The scientist should revise the question to address a gap in knowledge.
Physics
2 answers:
Rasek [7]2 years ago
6 0
Because of how it's worded the answer would most likely be number four                                                                                       

liq [111]2 years ago
6 0

Answer: The scientist should revise the question to address a gap in knowledge.

Explanation:

A research question is a scientific inquiry that is required to be answered using suitable methodology.

Among the options given, The scientist should revise the question to address a gap in knowledge. is the correct option. This is because of the fact that analyzing and finding the possibilities in the question again the scientist can add new facts in the question which have not been found out by the research conducted by the several scientists earlier. This will lead to the increment in the knowledge related to the research topic.

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Define couple and give 2 examples
Elodia [21]

Answer:

Two equal and opposite parallel forces not acting along the same line, form a couple. A couple is always needed to produce the rotation.

For example, turning a key in a lock and turning a steering wheel.

3 0
1 year ago
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Write difference between upstroke and downstroke of water pump
lakkis [162]

Explanation:

Upstroke is a mechanism which helps to raise the plunger and downstroke helps to help lower the plunger. On the up-stroke of the plunger, the lower valve opens and the upper valve is closed. ... Whereas, on the downstroke, the lower valve closes and the upper one opens.

7 0
1 year ago
A 600g toy train completes 10 laps of its circular track in 1 min 20s. If the radius of the track is 1.2 m, Find the centripetal
Lynna [10]

Wow !  This will take more than one step, and we'll need to be careful
not to trip over our shoe laces while we're stepping through the problem.

The centripetal acceleration of any object moving in a circle is

                          (speed-squared)  /  (radius of the circle)  .

Notice that we won't need to use the mass of the train.

We know the radius of the track.  We don't know the trains speed yet,
but we do have enough information to figure it out.  That's what we
need to do first.

Speed  =  (distance traveled) / (time to travel the distance).

Distance = 10 laps of the track.   Well how far is that ? ? ?

1 lap = circumference of the track = (2π) x (radius) =  2.4π  meters

10 laps =  24π  meters.

Time = 1 minute 20 seconds  =  80 seconds

The trains speed is  (distance) / (time)

                               =  (24π meters) / (80 seconds)

                               =        0.3 π  meters/second .

NOW ... finally, we're ready to find the centripetal acceleration.

                                 <span> (speed)²  /  (radius)

                           =    (0.3π m/s)²  /  (1.2 meters)

                           =    (0.09π m²/s²)  /  (1.2 meters)

                           =    (0.09π  /  1.2)   m/s²

                           =          0.236  m/s²  .        (rounded)

If there's another part of the problem that wants you to find
the centripetal FORCE ...

Well,       Force = (mass) · (acceleration) .

We know the mass, and we ( I ) just figured out the acceleration,
so you'll have no trouble calculating the centripetal force.       </span>
4 0
1 year ago
A stone weighing 1.5 kilograms is resting on a rock at a height of 20 meters above the ground. The stone rolls down 10 meters an
34kurt
Given that the equation for the potential energy of an object is: PE = mgh, where, m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the ground, simply substitute the given values to obtain the potential energy. In this case, m = 1.5 kg, g = 9.8 N/kg, and h = 10 m. The height is set to 10 m since this is the height of the moss above the ground after it fell. Thus, the potential energy of the moss at its position is 147 Joules. 
4 0
1 year ago
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A constant braking force of 10 newtons applied for 5 seconds is used to stop a 2.5-kilogram cart traveling at 20 meters per seco
ss7ja [257]
Mathematically it can be expressed as: I = FpΔt. Where F p is the average magnitude of the acting force and Δt = t 2 - t 1, the time lapse in the force acts.
 The magnitude of the impulse applied to stop the cart is
 I = FpΔt = (10N) * (5s) = 50 N.s
6 0
1 year ago
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