Initial speed of the coin (u)= 0 (As the coin is released from rest)
Acceleration due to gravity (a) = g = 9.81 m/s²
Time of fall (t) = 1.5 s
From equation of motion we have:
By substituting values in the equation, we get:
v = 0 + 9.81 × 1.5
v = 14.715 m/s
Speed of the coin as it hits the ground/Final speed of the coin = 14.715 m/s
Answer:
Explanation:
Given:
Initial velocity of the vehicle,
distance between the car and the tree,
time taken to respond to the situation,
acceleration of the car after braking,
Using equation of motion:
..............(1)
where:
final velocity of the car when it hits the tree
initial velocity of the car when the tree falls
acceleration after the brakes are applied
distance between the tree and the car after the brakes are applied.
Now for this situation the eq. (1) becomes:
(negative sign is for the deceleration after the brake is applied to the car.)
Answer:
Spring constant, k = 24.1 N/m
Explanation:
Given that,
Weight of the object, W = 2.45 N
Time period of oscillation of simple harmonic motion, T = 0.64 s
To find,
Spring constant of the spring.
Solution,
In case of simple harmonic motion, the time period of oscillation is given by :
m is the mass of object
m = 0.25 kg
k = 24.09 N/m
or
k = 24.11 N/m
So, the spring constant of the spring is 24.1 N/m.