If 300. mL of water are poured into the measuring cup, the volume reading is 10.1 oz . This indicates that 300. mL and 10.1 oz a
2 answers:
Answer : 29.7 mL are in a fluid ounce based on this data.
Explanation :
As we are given that 300 mL and 10.1 oz are equivalent. That means,
300 mL = 10.1 oz
or,
10.1 oz = 300 mL
Now we have to determine the volume of fluid in milliliters.
As, 10.1 oz of fluid = 300 mL
So, 1 oz of fluid =
= 29.7 mL
Therefore, 29.7 mL are in a fluid ounce based on this data.
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Answer:
a). Determine the magnitude of the gravitational force exerted on each by the earth.
Rock:
Pebble:
(b)Calculate the magnitude of the acceleration of each object when released.
Rock:
Pebble:
Explanation:
The universal law of gravitation is defined as:
(1)
Where G is the gravitational constant, m1 and m2 are the masses of the two objects and r is the distance between them.
<em>Case for the rock </em><em>:</em>
m1 will be equal to the mass of the Earth and since the rock and the pebble are held near the surface of the Earth, then, r will be equal to the radius of the Earth
.
Newton's second law can be used to know the acceleration.
(2)
<em>Case for the pebble </em><em>:</em>
Answer:
Explanation:
Given that,
The radius of sphere, r = 5 cm = 0.05 m
Net charge carries, q = 7.5 µC = 7.5 × 10⁻⁶ C
We need to find the surface charge density on the sphere. Net charge per unit area is called the surface charge density. So,
So, the surface charge density on the sphere is .