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2 years ago

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Current X is 2.5 A and runs for 39 seconds. Current Y is 3.8 A and runs for 24 seconds. Which current delivered more charge, and

how much more charge did it deliver?

1 answer:

Aleonysh [2.5K]2 years ago

7 0

Answer: B. Current x delivered 6.3 C more then Y

Explanation:

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a 2.0 kg hoop rolls without slipping on a horizontal surface so that its center proceeds to the right with a constant linear spe

e-lub [12.9K]

Answer:

72 J

Explanation:

Total kinetic energy will be tge sum of rotational and translational energy.

Rotational kinetic energy is given by $0.5I\omega^{2}$ where I is moment of inertia which is given by $mr^{2}$ and here m is mass, r is radius. Also, $v=\omega r$ hence making \omega the subject then $\omega=\frac {v}{r}$ where v is the velocity.

Rotational kinetic energy= $0.5I\omega^{2}=0.5mr^{2}\times(\frac {v}{r})^{2}= 0.5mv^{2}$

This is same as the formula for translational kinetic energy which is given by $0.5mv^{2}$

Therefore, total kinetic energy= $0.5mv^{2}+0.5mv^{2}=mv^{2}$

Substituting m with 2 kg and v with 6 m/s then total energy will be $2\times 6^{2}=72 J$

7 0

2 years ago

A ball of mass 0.4 kg is initially at rest on the ground. It is kicked and leaves the kicker's foot with a speed of 5.0 m/s in a

yawa3891 [41]

Answer:

the answer the correct is 3

Explanation:

Let's use the relationship between momentum and momentum

I = Δp

I = m $v_{f}$ - m v₀

Let's calculate

I = 0.4 5.0 - 0

I = 2.0 N s

By Newton's law of action and reaction the force on the ball is equal to the force that the ball exerts on the foot, therefore the impulse on the foot of equal magnitude, but in the opposite direction

I = 2.0 Ns with 60°

When reviewing the answer the correct is 3

4 0

2 years ago

The diagram shows a heater above a thermometer. The thermometer bulb is in the position shown. Which row shows how the heat ener

balu736 [363]

Answer:

The diagram shows a heater above a thermometer. The thermometer bulb is in the position shown. How the heat

5 0

2 years ago

The drawing shows an adiabatically isolated cylinder that is divided initially into two identical parts by an adiabatic partitio

Sveta_85 [38]

Answer:

temperature on left side is 1.48 times the temperature on right

Explanation:

GIVEN DATA:

$\gamma = 5/3$

T1 = 525 K

T2 = 275 K

We know that

$P_1 = \frac{nRT_1}{v}$

$P_2 = \frac{nrT_2}{v}$

n and v remain same at both side. so we have

$\frac{P_1}{P_2} = \frac{T_1}{T_2} = \frac{525}{275} = \frac{21}{11}$

$P_1 = \frac{21}{11} P_2$ ..............1

let final pressure is P and temp $T_1 {f} and T_2 {f}$

$P_1^{1-\gamma} T_1^{\gamma} = P^{1 - \gamma}T_1 {f}^{\gamma}$

$P_1^{-2/3} T_1^{5/3} = P^{-2/3} T_1 {f}^{5/3}$ ..................2

similarly

$P_2^{-2/3} T_2^{5/3} = P^{-2/3} T_2 {f}^{5/3}$ .............3

divide 2 equation by 3rd equation

$\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}$

$T_1 {f} = 1.48 T_2 {f}$

thus, temperature on left side is 1.48 times the temperature on right

6 0

2 years ago

A 12.0-kg shell is launched at an angle of 55.0 ∘ above the horizontal with an initial speed of 150 m/s. when it is at its highe

Stolb23 [73]

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2 years ago