what is the resistance of a car light bulb that conducts 0.025A current when connected to a 12V car accumulator? is the current
1 answer:
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Answer:
a) Q = C*emf
b) Reduction in electric field strength and electric potential
c) Initial current through the resistor = emf/R
d) The final charge = K*C*emf
Explanation:
a) The resistors and capacitors are connected in series with the battery
Using Kirchoff's voltage law, sum of all voltages in the circuit is zero
Let = Voltage dropped across the Resistor
= Voltage dropped across the capacitor
Applying KVL;
.........................(1)
Since the connection is in series, the same current flow through the circuit
Putting and
into equation (1)
At the final charge, the capacitor in fully charged, and current drops to zero due to equilibrium
b) Current starts running through the plate because as the sheet of plastic is inserted between the plates both the electric field intensity and the electric potential reduces. The charge also reduces, then current flows
c) The current through the resistor is the current through the entire circuit ( series connection)
Putting the values of t and I₀ into the formula for I written above
d) NB: The initial charge on the capacitor = C * emf
The final charge will be:
D. Atoms.
Explanation:
All the matter is made of elementary particles called "atoms".
Further, an atom is made of electrons, protons and neutrons. The electrons & protons are again made of the fundamental sub-particles, electrons (leptons) and the protons(quarks).
The classification of particles is shown in the figure attached
