Kinetic energy is calculated through the equation,
KE = 0.5mv²
At initial conditions,
m₁: KE = 0.5(0.28 kg)(0.75 m/s)² = 0.07875 J
m₂ : KE = 0.5(0.45 kg)(0 m/s)² = 0 J
Due to the momentum balance,
m₁v₁ + m₂v₂ = (m₁ + m₂)(V)
Substituting the known values,
(0.29 kg)(0.75 m/s) + (0.43 kg)(0 m/s) = (0.28 kg + 0.43 kg)(V)
V = 0.2977 m/s
The kinetic energy is,
KE = (0.5)(0.28 kg + 0.43 kg)(0.2977 m/s)²
KE = 0.03146 J
The difference between the kinetic energies is 0.0473 J.
Answer:
a.

Explanation:
a. Find the probability that exactly one photo detector of a pair is acceptable:
Let
photo is accepted and the probability
is defected.
Therefore:

#The probability of exactly one photo detector of a pair is accepted is 7/25
b.Find the probability that both photo detectors in a pair are defective,P(D1D2):

Hence, from out tree diagram,the probability that both photo detectors in a pair are defective is 6/25
Answer:
The other angle is 30 degrees.
Explanation:
The range of projectile is given by :

Here,
u is the speed of launch of projectile
Here, 
We need to find the other launch angle when the projectile have the same range, such that,




So, the other angle is 30 degrees. Hence, this is the required solution.