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Rus_ich [418]
2 years ago
13

A 50 kg rocket generates 990 N of thrust. What will be its acceleration if it is launched straight up?

Physics
1 answer:
Ilia_Sergeevich [38]2 years ago
4 0

Answer:

The acceleration of the rocket is 10 m/s².

Explanation:

Let the acceleration of the rocket be a m/s².

Given:

Mass of the rocket is, m=50\ kg

Thrust force acting upward is, F_{th}=990\ N

Acceleration due to gravity is, g=9.8\ m/s^2

Now, force acting in the downward direction is due to the weight of the rocket and is given as:

W=mg=50\times 9.8=490\ N

Now, net force acting on the rocket in upward direction is given as:

F_{net}=F_{th}-W\\F_{net}=990-490=500\ N

Therefore, from Newton's second law, net force acting on the rocket is equal to the product of mass and acceleration.

F_{net}=ma\\500=50a\\a=\frac{500}{50}=10\ m/s^2

Therefore, the acceleration of the rocket is 10 m/s².

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Which of the following statements best represents the impact of evolutionary theory on the field of psychology?
grandymaker [24]

Answer- the correct option for the question would be choice number c which tells us about the natural selection process of human species.

Explanation- Evolution of psychology was studied under the given heads namely Behaviorism cognitive functionalism sociocultural Psychodynamic and structuralism.  

On studying the facts under these prospects the evolution of psychology gives us the idea of the selection by nature of individuals and the pattern of their behavior shown in different aspects.

8 0
2 years ago
) A physics student wants to measure the stiffness of a spring (force required per cm stretched). He knows that according to Hoo
Maurinko [17]

Answer:

Explanation:

find the solution below

3 0
2 years ago
What voltage is required to move 6A through 20?<br><br>​
Marina CMI [18]

Answer:

120V

Explanation:

Given parameters:

Current  = 6A

Resistance  = 20Ω

Unknown:

Voltage = ?

Solution:

According to ohms law;

           V = IR

Where V is the voltage

            I is the current

            R is the resistance

Now, insert the parameters and solve;

    V  = 6 x 20  = 120V

7 0
2 years ago
For a given initial projectile speed Vo, calculate what launch angle A gives the longest range R. Show your work, don't just quo
pickupchik [31]
The optimal angle of 45° for maximum horizontal range is only valid when initial height is the same as final height. 

<span>In that particular situation, you can prove it like this: </span>

<span>initial velocity is Vo </span>
<span>launch angle is α </span>

<span>initial vertical velocity is </span>
<span>Vv = Vo×sin(α) </span>

<span>horizontal velocity is </span>
<span>Vh = Vo×cos(α) </span>

<span>total time in the air is the the time it needs to fall back to a height of 0 m, so </span>
<span>d = v×t + a×t²/2 </span>
<span>where </span>
<span>d = distance = 0 m </span>
<span>v = initial vertical velocity = Vv = Vo×sin(α) </span>
<span>t = time = ? </span>
<span>a = acceleration by gravity = g (= -9.8 m/s²) </span>
<span>so </span>
<span>0 = Vo×sin(α)×t + g×t²/2 </span>
<span>0 = (Vo×sin(α) + g×t/2)×t </span>
<span>t = 0 (obviously, the projectile is at height 0 m at time = 0s) </span>
<span>or </span>
<span>Vo×sin(α) + g×t/2 = 0 </span>
<span>t = -2×Vo×sin(α)/g </span>

<span>Now look at the horizontal range. </span>
<span>r = v × t </span>
<span>where </span>
<span>r = horizontal range = ? </span>
<span>v = horizontal velocity = Vh = Vo×cos(α) </span>
<span>t = time = -2×Vo×sin(α)/g </span>
<span>so </span>
<span>r = (Vo×cos(α)) × (-2×Vo×sin(α)/g) </span>
<span>r = -(Vo)²×sin(2α)/g </span>

<span>To find the extreme values of r (minimum or maximum) with variable α, you must find the first derivative of r with respect to α, and set it equal to 0. </span>

<span>dr/dα = d[-(Vo)²×sin(2α)/g] / dα </span>
<span>dr/dα = -(Vo)²/g × d[sin(2α)] / dα </span>
<span>dr/dα = -(Vo)²/g × cos(2α) × d(2α) / dα </span>
<span>dr/dα = -2 × (Vo)² × cos(2α) / g </span>

<span>Vo and g are constants ≠ 0, so the only way for dr/dα to become 0 is when </span>
<span>cos(2α) = 0 </span>
<span>2α = 90° </span>
<span>α = 45° </span>
4 0
2 years ago
A car travels 10 m/s east. Another car travels 10 m/s north. The relative speed of the first car with respect to the second is:
Thepotemich [5.8K]

Answer:

d. less than 20m/s

Explanation:

To the 2nd car, the first car is travelling 10m/s east and 10m/s south. So the total velocity of the first car with respect to the 2nd car is

[tex]\sqrt{10^2 + 10^2} =10\sqrt{2}=14.14m/s

As 14.14m/s is less than 20m/s. d is the correct selection for this question.

3 0
2 years ago
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