Answer:
The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J
Explanation:
The given variables are
Work done = 550 J
Volume change = V₂ - V₁ = -0.5V₁
Thus the product of pressure and volume change = work done by gas, thus
P × -0.5V₁ = 500 J
Hence -PV₁ = 1000 J
also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂
Also to compress the gas by a factor of 11 we have
P (V₂ - V₁) = P×(V₁/11 -V₁) = P(11V₁ - V₁)/11 = P×-10V₁/11 = -PV₁×10/11 = 1000 J ×10/11 = 909.091 J of work
Answer:
Angular displacement of the turbine is 234.62 radian
Explanation:
initial angular speed of the turbine is



similarly final angular speed is given as



angular acceleration of the turbine is given as

now we have to find the angular displacement is given as



Please provide the choices to select the possible choices.
Answer:
B. Trial 2
Explanation:
Trial 2, because the student’s finger applied the largest force to the sensor.
Because the trial 2 student finger applied to largest force.
Answer:
1.17894 m
Explanation:
The rock is at one end of the rod which is 0.211 m from the fulcrum
F = Force
d = Distance
L = Length of rod
M = Mass of rock = 325 kg
g = Acceleration due to gravity = 9.81 m/s²
Torque

Torque of man

Torque of rock

The torques acting on the system is conserved

The length of the rod is 1.17894 m