Answer: deceleration of 
Explanation:
Given
Car is traveling at a speed of u=20 m/s
The diameter of the car is d=70 cm
It slows down to rest in 300 m
If the car rolls without slipping, then it must be experiencing pure rolling i.e. 
Using the equation of motion
Insert 
Write acceleration as
So, the car must be experiencing the deceleration of .
The solution for this problem would be:(10 - 500x) / (5 - x)
so start by doing:
x(5*50*2) - xV + 5V = 0.02(5*50*2)
500x - xV + 5V = 10
V(5 - x) = 10 - 500x
V = (10 - 500x) / (5 - x)
(V stands for the volume, but leaves us with the expression for x)
Answer: 5.97, 24
m = 5.97
n = 24
SN = 5.97 × 10^24 kg
Explanation:
Scientific notation or standard form is a way of rewriting very large or very small (minute) numbers in conveniently in decimal form. The standard way of writing scientific notation is of the form;
m × 10^n
To derive m, we need to reduce it to a number between 1 and 10 ( 10 exclusive)
For the case above ;
m = 5.97
To get the value of n, we need to count the number of digits from the right egde of the data to the point where we put the decimal.
For the case above;
n = 24
Therefore, the scientific notation of the mass of the earth is ;
M = 5.97 × 10^24 kg
Answer:
a = 3 m/s²
Explanation:
given,
mass of crate = 20 Kg
horizontal force on crate = 70 N
frictional force on the crate = 10 N
acceleration of crate = ?
now, calculating net force acting on the crate.
F = horizontal force - frictional force
F = 70 - 10
F = 60 N
net force on the crate is equal to 60 N.
We also know that
F = m a
60 = 20 x a
a = 3 m/s²
Hence, the acceleration of the crate is equal to 3 m/s²
Explanation:
It is given that, the volume of air is 53.28 m³. We need to convert it into scientific notation.
Any number in scientific notation can be given by :
a is real no and b is any integer
We have, V = 53.28 m³
To write it into scientific notation, shift decimal before 3 such that,
No multiply and divide by 10. So,
So, the correct option is (a).
