answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timofeeve [1]
2 years ago
11

When holes are drilled through the wall of a water tower, water will spurt out the greatest horozontal distance from the hole cl

osest to?
Physics
1 answer:
Mnenie [13.5K]2 years ago
3 0

Bottom of the water tower

Explanation:

When holes are drilled through the wall of a water tower, water will spurt out the greatest horizontal distance from the hole closest to the bottom of the water tower.

This is because the near the bottom of the tower is the greatest compared to other parts of the tower.

  • The pressure increases with depth.
  • As the depth of water increases, the column of water above exerts more pressure on the one below.
  • Therefore, water will spurt out more from the bottom of the tower compared to the top of the tower.

Learn more:

Pressure brainly.com/question/4868239

#learnwithBrainly

You might be interested in
A ball is released from a tower at a height of 100 meters toward the roof of another tower that is 25 meters high. The horizonta
Sindrei [870]
Let's figure out how long it will take to fall 75 meters, from the 1st roof to the second roof. We can assume that gravity is the only force affecting vertical velocity, so the ball starts from rest and accelerates downward at g, or -9.8m/s².

Let's find how long it takes to fall 75 meters:
s(t) = Vi + (1/2)*a*t²,
where s(t) is displacement as a function of time, Vi is initial velocity (zero), and a is acceleration. Plugging in our values:
-75 = 0 + (1/2)(-9.8)(t²)      Multiply both sides by 2/-9.8
15.3 = t²                             Take the square root of both sides
t = 3.91

We need to the ball to travel 20 meters horizontally before it hits the roof in 3.91 seconds. We can assume that the horizontal velocity remains constant (a=0, Vi=V(t) for all t). 
Therefore, the minimum horizontal velocity is:
D = V*t , simple distance formula, distance equals velocity times time:
20 = V * 3.91       Divide both sides by 3.91
V = 5.11

The horizontal velocity, therefore, must be at least 5.11m/s in order for the ball to reach the roof of the second building. 
3 0
2 years ago
A frog leaps up from the ground and lands on a step 0.1 m above the ground 2 s later. We want to find the vertical velocity of t
zhuklara [117]

Answer:

<em>You would use the kinematic formula:</em>

    \Delta y=V_{0y}\times t-g\times t^2/2

Explanation:

The upwards vertical motion is ruled by the equation:

        y=y_0+V_{0y}\times t-g\times t^2/2

Where:

       y \text{ is the position at the time }t:y=0.1m

       y_0\text{ is the initial position: }y_0=0

       t=2s

       g\text{ is the gravitational acceleration: }\approx 9.8m/s^2

       V_{0y}\text{ is the initial vertical velocity}

Naming Δy = y - y₀, the equation becomes:

      \Delta y=V_{0y}\times t-g\times t^2/2

Then, you just need to substitute with Δy = 0.1m, t = 2s, and g = 9.8m/s², ans solve for the intital vertical velocity.

7 0
2 years ago
Read 2 more answers
The loudness of a sound is inversely proportional to the square of your distance from the source of the sound. if your friend is
kirill [66]
Let loudness be L, distance be d, and k be the constant of variation such that the equation that would best represent the given above is,
                    L = k/(d^2)
For Case 1,
                       L1 = k/(d1^2)
For Case 2,
                       L2 = k/((d1/4)^2)
For k to be equal, L1 = 16L2. 
Therefore, the loudness at your friend's position is 16 times that of yours. 
5 0
2 years ago
Read 2 more answers
A 0.300kg glider is moving to the right on a frictionless, ­horizontal air track with a speed of 0.800m/s when it makes a head-o
e-lub [12.9K]

Answer:

The final velocity of the first glider is 0.27 m/s in the same direction as the first glider

The final velocity of the second glider is 1.07 m/s in the same direction as the first glider.

0.010935 J

0.0858675 J

Explanation:

m_1 = Mass of first glider = 0.3 kg

m_2 = Mass of second glider = 0.15 kg

u_1 = Initial Velocity of first glider = 0.8 m/s

u_2 = Initial Velocity of second glider = 0 m/s

v_1 = Final Velocity of first glider

v_2 = Final Velocity of second glider

As momentum and Energy is conserved

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

{\tfrac {1}{2}}m_{1}u_{1}^{2}+{\tfrac {1}{2}}m_{2}u_{2}^{2}={\tfrac {1}{2}}m_{1}v_{1}^{2}+{\tfrac {1}{2}}m_{2}v_{2}^{2}

From the two equations we get

v_{1}=\frac{m_1-m_2}{m_1+m_2}u_{1}+\frac{2m_2}{m_1+m_2}u_2\\\Rightarrow v_1=\frac{0.3-0.15}{0.3+0.15}\times 0.8+\frac{2\times 0.15}{0.3+0.15}\times 0\\\Rightarrow v_1=0.27\ m/s

The final velocity of the first glider is 0.27 m/s in the same direction as the first glider

v_{2}=\frac{2m_1}{m_1+m_2}u_{1}+\frac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\frac{2\times 0.3}{0.3+0.15}\times 0.8+\frac{0.3-0.15}{0.3+0.15}\times 0\\\Rightarrow v_2=1.067\ m/s

The final velocity of the second glider is 1.07 m/s in the same direction as the first glider.

Kinetic energy is given by

K=\frac{1}{2}m_1v_1^2\\\Rightarrow K=\frac{1}{2}0.3\times 0.27^2\\\Rightarrow K=0.010935\ J

Final kinetic energy of first glider is 0.010935 J

K=\frac{1}{2}m_2v_2^2\\\Rightarrow K=\frac{1}{2}0.15\times 1.07^2\\\Rightarrow K=0.0858675\ J

Final kinetic energy of second glider is 0.0858675 J

6 0
2 years ago
Koala bears can eat only certain kind of Australian eucalyptus leaves.koalas are considered
DaniilM [7]
<em>Hello there, and thank you for asking your question here on brainly.

<u>Answer: Koala bears are considered herbivores, or as in the scientific name, arboreal herbivorous marsupial, marsupial because it also carries it's babies around in a pouch. Koala bears are also native to Australia, which eucalyptus leaves are also native to.
</u>
Hope this helped you! ♥</em>
3 0
2 years ago
Other questions:
  • It takes 146./kjmol to break an oxygen-oxygen single bond. calculate the maximum wavelength of light for which an oxygen-oxygen
    8·1 answer
  • Two wheels are identical but wheel b is spinning with twice the angular speed of wheel
    8·1 answer
  • 2. An airplane traveling north at 220. meters per second encounters a 50.0-meters-per-second crosswind
    13·1 answer
  • The Sun orbits the center of the Milky Way galaxy once each 2.60 × 108 years, with a roughly circular orbit averaging 3.00 × 104
    6·1 answer
  • Suppose the door of a room makes an airtight but frictionless fit in its frame. Do you think you could open the door if the air
    9·1 answer
  • Many gates at railway crossings are operated manually. A typical gate consists of a rod usually made of iron, consisting heavy w
    5·1 answer
  • The motion of a particle connected to a spring is described by x = 10 sin (pi*t). At
    8·1 answer
  • Materials Science and Engineering is the study of material behavior &amp; performance and how this is simultaneously related to
    14·1 answer
  • Rubber rods charged by rubbing with cat fur repel each other. Glass rods charged by rubbing with silk repel each other. A rubber
    13·1 answer
  • Which property best makes radio waves safe for diagnosing illnesses through magnetic resonance imaging?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!