Consider two slides, both of the same height. One is long and the other is short. From which slide will a child have a greater f
1 answer:
Answer:
The final speed will be the same for the children on the shorter side and on the longer side.
Explanation:
This is because since the they are the same distance above the ground, their potential energy which is a function of mass, acceleration due to gravity and vertical height are the same.
PE = Mass × gravity × vertical height
At this point, we can deduce that the horizontal length of the slide has no effect on the potential energy. Only the vertical height does.
All this potential energy is converted to kinetic energy at the end of the slide. Since the potential energy is the same, then the kinetic energy will be the same and thus their velocity is the same.
Mathematically, consider that PE = mgh and KE = m
at the bottom of the slide, since energy has to be conserved, PE must be equal to KE.
mgh = m
final velocity of the child , v =
It shows the final velocity is only a function f acceleration due to gravity and height.
Thus, making their velocities equal.
You might be interested in
Answer:
(a) The magnitude of the lift force is 52144.71 N, approximately.
(b) The magnitude of the air resistance force opposing the movement is 17834.54 N, approximately.
Explanation:
Since the helicopter is moving horizontally at a constant velocity, we can assume that the net force acting on it is zero, then
(a) in the vertical direction we have
.
(b) Now horizontally,
- The largest increase in potential energy occurs when the charge is moving north. This is because the charge is negative, so it acquires potential energy when moving in the same direction of the field (viceversa, a positive charge when moving in the direction of the field it loses potential energy converting it into kinetic energy). The amount of potential energy gained is equal to the product of the charge and the distance covered:
- The second largest increase is when the charge is moving east. In this case, actually, the variation of potential energy is zero. This is because the charge is moving perpendicular to the field, and so it is moving along points with same potential. Therefore, in this case the variation of potential energy is zero:
- Finally, when the charge is moving south, it loses potential energy. This is because it is moving against the electric field, and since it is a negative charge, in this direction it loses potential energy converting it into kinetic energy. Therefore, in this case:
- The second largest increase is when the charge is moving east. In this case, actually, the variation of potential energy is zero. This is because the charge is moving perpendicular to the field, and so it is moving along points with same potential. Therefore, in this case the variation of potential energy is zero:
- Finally, when the charge is moving south, it loses potential energy. This is because it is moving against the electric field, and since it is a negative charge, in this direction it loses potential energy converting it into kinetic energy. Therefore, in this case: