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2 years ago

Honeybees can see light in the ________ range of the electromagnetic spectrum.

1 answer:

4 0

Humans can see wavelengths in the visible part of the electromagnetic spectrum. That is the range of approximately 400 - 700 nm. Honeybees can see visible light and about 100 nm more in the ultraviolet part of the electromagnetic spectrum. That is approximately 300 - 700 nm.

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Deep-sea divers often breathe a mixture of helium and oxygen to avoid getting the "bends" from breathing high-pressure nitrogen.

kvv77 [185]

Answer:

0.69444 m, 0.08152 m, 0.32407 m, 0.03804 m

Explanation:

v = Velocity of sound

f = Frequency

Length of vocal tract is given by

$L=\dfrac{v}{4f}$

At f = 270 Hz v = 750 m/s

$L=\dfrac{750}{4\times 270}\\\Rightarrow L=0.69444\ m$

At f = 2300 Hz v = 750 m/s

$L=\dfrac{750}{4\times 2300}\\\Rightarrow L=0.08152\ m$

At f = 270 Hz v = 350 m/s

$L=\dfrac{350}{4\times 270}\\\Rightarrow L=0.32407\ m$

At f = 2300 Hz v = 350 m/s

$L=\dfrac{350}{4\times 2300}\\\Rightarrow L=0.03804\ m$

3 0

2 years ago

Which statements describe how chemical formulas, such as H2O, represent compounds? Check all that apply.

Pani-rosa [81]

The statements that apply in this case are:

They show the elements that make up a compound.

They show the types of atoms that make up a molecule.

They show the number of each type of atom in a molecule.

5 0

2 years ago

Read 2 more answers

Astronomers have discovered several volcanoes on io, a moon of jupiter. one of them, named loki, ejects lava to a maximum height

r-ruslan [8.4K]

The question seems to be incomplete. However, I can think of a possible logical question this problem could have. The equation for the maximum height attained by any object thrown upwards is:

H = v²/2g

I think the question would be determining the gravity in Io assuming that the initial velocity of the lava is the same. Then, the solution is as follows:

Let's use the other volcano to find v.
1.89×10⁵ m = v²/2(1.72 m/s²)
Solving for v,
v = 806.325 m/s

So, we use this to find g in Io.
2×10⁵ m = (806.325)²/2(g)
Solving for g,
<em>g = 1.6254 m/s²</em>

7 0

2 years ago

A car rounds an unbanked curve of radius 65 m. If the coefficient of static friction between the road and car is 0.70, what is t

True [87]

Answer:

v = 21.127 m/s

Explanation:

Let's start off with the equation for centrifugal force:

$F = m*v^2 / r$

This force has to be equal to the force of friction which is:

$F=u * R$ (where u = coefficient of friction and R = mass * gravity )

Assumption: The car is travelling on horizontal ground

We can set the above equations equal to one another to get:

(m*v^2)/r = u * (m * 9.81)

here u = 0.7

r = 65

and mass cancels out on each side

Solving for v, we get:

v = 21.127 m/s

3 0

2 years ago

A radioactive source has a half life of 80s.

Burka [1]

Lets make the original number of nuclides at the start is 100.

If 7/8 of 100 is decayed, that means 87.5 decayed.

$\frac{7}{8} \times 100 = 87.5$

And there is 1/8 left of the number of nuclide 100. Which is 12.5

$100 - 87.5 =12.5$

$\frac{1}{8} \times 100 = 12.5$

How many Half lifes passed for 100 to become 12.5 is 3 Half-Lives.

$100 \div 2 \div 2 \div 2 = 12.5$

Each Half-Life is 80 seconds so there is 240 seconds

$3 \times 80 = 240$ The answer is that it takes 240 seconds.

6 0

2 years ago