Answer:
Explanation:
As the disc is unrolling from the thread then at any moment of the time
We have force equation as
also by torque equation we can say
Now we have
Also from above equation the tension force in the string is
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Answer:
The magnitude of the torque on the loop due to the magnetic field is .
Explanation:
Given that,
Diameter = 10 cm
Current = 0.20 A
Magnetic field = 0.30 T
Unit vector
We need to calculate the torque on the loop
Using formula of torque
Where, N = number of turns
A = area
I = current
B = magnetic field
Put the value into the formula
Hence, The magnitude of the torque on the loop due to the magnetic field is .
Answer:
F= 2666.66 N
N=334.22 RPM
Explanation:
Given that
Diameter of pulley ,d= 0.15 m
Radius ,r= 0.075 m
Torque ,T= 200 N.m
Power ,P = 7 kW
Lets take force = F
T = F .r
Now by putting the values
F= 2666.66 N
Lets take rotational speed = N RPM
We know that
Now by putting the values in the above equation
N=334.22 RPM