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Korolek [52]
2 years ago
9

The Lyman series comprises a set of spectral lines. All of these lines involve a hydrogen atom whose electron undergoes a change

in energy level, either beginning at the n = 1 level (in the case of an absorption line) or ending there (an emission line).
The inverse wavelengths for the Lyman series in hydrogen are given by:
1/λ = RH (1 - 1/n^2) ,
where n = 2, 3, 4, and the Rydberg constant RH = 1.097 x 10^7 m^−1. (Round your answers to at least one decimal place. Enter your answers in nm.)
(a) Compute the wavelength for the first line in this series (the line corresponding to n = 2).
(b) Compute the wavelength for the second line in this series (the line corresponding to n = 3).
(c) Compute the wavelength for the third line in this series (the line corresponding to n = 4).
(d) In which part of the electromagnetic spectrum do these three lines reside?
O visible light region
O infrared region
O ultraviolet region
O gamma ray region
O x-ray region
Physics
1 answer:
mihalych1998 [28]2 years ago
8 0

Answer:

a) 1.2*10^-7 m

b) 1.0*10^-7 m

c) 9.7*10^-8 m

d) ultraviolet region

Explanation:

To find the different wavelengths you use the following formula:

\frac{1}{\lambda}=R_H(1-\frac{1}{n^2})

RH: Rydberg constant = 1.097 x 10^7 m^−1.

(a) n=2

\frac{1}{\lambda}=(1.097*10^7m^{-1})(1-\frac{1}{(2)^2})=8227500m^{-1}\\\\\lambda=1.2*10^{-7}m

(b)

\frac{1}{\lambda}=(1.097*10^7m^{-1})(1-\frac{1}{(3)^2})=9751111,1m^{-1}\\\\\lambda=1.0*10^{-7}m

(c)

\frac{1}{\lambda}=(1.097*10^7m^{-1})(1-\frac{1}{(4)^2})=10284375m^{-1}\\\\\lambda=9.7*10^{-8}m

(d) The three lines belong to the ultraviolet region.

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1 year ago
A rigid tank whose volume is unknown is divided into two parts by a partition. One side of the tank contains an ideal gas at 935
a_sh-v [17]

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2805 °C

Explanation:

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P=RTn/V

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In the initial situation the gas have an initial volume V_{i}, temperature T_{i}, and pressure P,.

And in the final situation the gas have different volume V_{f} and temeperature T_{f}, the same pressure P,, and the same number of moles n,.

We can write the gas ideal equation for each state:

P=RT_{i}n/V_{i} and P=RT_{f}n/V_{f}, as the pressure are equals in both states we can write

RT_{i}n/V_{i} = RT_{f}n/V_{f}

solving for T_{f}

T_{f} = T_{i}/V_{i} * V_{f} (*)

We know T_{i}  = 935 °C, and that the V_{f} (the complete volume of the tank) is the initial volume V_{i} plus the part initially without gas which has a volume twice the size of the initial volume (read in the statement: the other side has a volume twice the size of the part containing the gas). So the final volume  V_{f}= V_{i} + 2V_{i}=3V_{i}

Replacing in (*)

T_{f} = 935/V_{i} * 3V_{i} = 935*3= 2805

7 0
1 year ago
Temperature and kinetic energy are ___________ proportional. adirectly directly indirectly 2. Heat is a measure of _____________
Usimov [2.4K]

Explanation:

It is known that relation between kinetic energy and temperature is as follows.

        K.E \propto \frac{3}{2}kT

Hence, kinetic energy is directly proportional to temperature.

Thermal energy is defined as the energy present within the molecules of an object due to the motion of particles. Basically, thermal energy is internal energy of an object.

Thus, we can conclude that:

  • Temperature and kinetic energy are directly proportional.
  • Heat is a measure of thermal energy.
  • Temperature is proportional to the total kinetic energy.
7 0
2 years ago
Read 2 more answers
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