On a dry day, just after washing your hair to remove natural oils and drying it thoroughly, run a plastic comb through it. Small
1 answer:
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Answer:
a. Springs oscillate with the same frequency
Explanation:
As they both are in the same height at equilibrium, so
weight of ball must be balanced with spring force, that is
k×x=mg
k= stiffness constant of spring
x=distance stretched
g= acceleration due to gravity
so, we can write
k/m=g/x
as the g is a constant and they stretched to same distance x so the g/x term becomes constant and
and k/m is same for both the springs so they will oscillate at the same frequency.
hence option a is correct.
Answer:
circuit sketched in first attached image.
Second attached image is for calculating the equivalent output resistance
Explanation:
For calculating the output voltage with regarding the first image.
For the calculus of the equivalent output resistance we apply thevenin, the voltage source is short and current sources are open circuit, resulting in the second image.
so.
Taking into account the %5 tolerance, with the minimal bound for Voltage and resistance.
if the -5% is applied to both resistors the Voltage is still 5V because the quotient has 5% / 5% so it cancels. to be more logic it applies the 5% just to one resistor, the resistor in this case we choose 2k but the essential is to show that the resistors usually don't have the same value. applying to the 2k resistor we have:
so.
Remember your kinematic equations for constant acceleration. One of the equations is 
, where 
= final position, 
= initial position, 
= initial velocity, t = time, and a = acceleration.
Your initial position is where you initially were before you braked. That means = 100m. You final position is where you ended up after t seconds passed, so = 350m. The time it took you to go from 100m to 350m was t = 8.3s. You initial velocity at the initial position before you braked was = 60.0 m/s. Knowing these values, plug them into the equation and solve for a, your acceleration:
Your acceleration is approximately
.
Your initial position is where you initially were before you braked. That means
Your acceleration is approximately