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FromTheMoon [43]
2 years ago
7

A 72 kg sled Is pulled forward from rest by a snowmobile and accelerates at 2 m/s squared forward for five seconds. The force of

friction acting on the sled is 120 N backwards. The total mass of the snowmobile and driver is 450 kg. The drag force acting on the snowmobile is 540 N backwards. What is the tension in the rope.
Physics
1 answer:
Inga [223]2 years ago
3 0
So first make a force diagram. I would label forward forces + and backward forces -. Essentially, the drag force is equal to the Ft (force of tension) + Ff (force of friction on snowmobile - driver system). The force of Friction is equal to mu * Fn. We can find mu through the force of friction acting on the sled. 120 N = mu * Fn (equal to m * g of sled). mu of the Ice is equal to 0.167. So, 540 N = Ft + 0.167 * 4500 N. Ft = -211.5 N. <u>Ft is acting in the backwards direction at a magnitude of 211.5 N</u>
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koban [17]

Answer:

D) 42.87 m/s

Explanation:

First, find the time it takes him to land.  Given in the y direction:

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Δy = v₀ t + ½ at²

60 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 3.5 s

Next, find the speed needed to travel the horizontal distance in that time.  Given in the x direction:

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150 m = v₀ (3.5 s) + ½ (0 m/s²) (3.5 s)²

v₀ = 42.87 m/s

4 0
2 years ago
The blood plays an important role in removing heat from th ebody by bringing the heat directly to the surface where it can radia
BabaBlast [244]

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Solving this : K =( 75 x 0.740 x 10^-3)/ 2 x (37-30)

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Answer:

The angle between the blue beam and the red beam in the acrylic block is  

 \theta _d  =0.19 ^o

Explanation:

From the question we are told that

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     The  wavelength of the blue light is F  =  486.1 nm  =  486.1 *10^{-9} \ m

    The  refractive index of the transparent acrylic plastic for red light is  n_C  =  1.488

       The  wavelength of the red light is C =  656.3 nm  = 656.3 *10^{-9} \  m

    The incidence angle is  i  =  45^o

Generally from Snell's law the angle of refraction of the blue light  in the acrylic block  is mathematically represented as

       r_F =  sin ^{-1}[\frac{sin(i) *  n_a }{n_F} ]

Where  n_a is the refractive index of air which have a value ofn_a =  1

So

     r_F =  sin ^{-1}[\frac{sin(45) *  1 }{ 1.497} ]

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Generally from Snell's law the angle of refraction of the red light in the acrylic block is mathematically represented as

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So

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The angle between the blue beam and the red beam in the acrylic block

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substituting values

       \theta _d  = 28.37 -  28.18

       \theta _d  =0.19 ^o

 

4 0
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Answer:

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