Answer:
1.25377 m/s²
Explanation:
m = Mass of person
g = Acceleration due to gravity = 9.81 m/s²
= Coefficient of friction
= Slope
From Newton's second law
Applying to the above equation and 
The acceleration of the same skier when she is moving down a hill is 1.25377 m/s²
Answer: C.
Explanation:
i choose B and got it wrong it told me the answer after on edge.
Answer: m= 35.6 kg
Explanation:
For finding the mass of the stone we have the formula
v= 
Here, Tension= m*g = m*9.81
and linear mass density= 
Linear mass density= 
Linear mass density= 0.0127 kg/m
Velocity= 
Velocity= 2 * 
Velocity= 165.8 m/s
So putting all these values in equation we get
v=
165.8= 
Solving we get
m= 35.58 kg
or m= 35.6 kg
Answer:
a) f = 615.2 Hz b) f = 307.6 Hz
Explanation:
The speed in a wave on a string is
v = √ T / μ
also the speed a wave must meet the relationship
v = λ f
Let's use these expressions in our problem, for the initial conditions
v = √ T₀ /μ
√ (T₀/ μ) = λ₀ f₀
now it indicates that the tension is doubled
T = 2T₀
√ (T /μ) = λ f
√( 2To /μ) = λ f
√2 √ T₀ /μ = λ f
we substitute
√2 (λ₀ f₀) = λ f
if we suppose that in both cases the string is in the same fundamental harmonic, this means that the wavelength only depends on the length of the string, which does not change
λ₀ = λ
f = f₀ √2
f = 435 √ 2
f = 615.2 Hz
b) The tension is cut in half
T = T₀ / 2
√ (T₀ / 2muy) = f = λ f
√ (T₀ / μ) 1 /√2 = λ f
fo / √2 = f
f = 435 / √2
f = 307.6 Hz
Traslate
La velocidad en una onda en una cuerda es
v = √ T/μ
ademas la velocidad una onda debe cumplir la relación
v= λ f
Usemos estas expresión en nuestro problema, para las condiciones iniciales
v= √ To/μ
√ ( T₀/μ) = λ₀ f₀
ahora nos indica que la tensión se duplica
T = 2T₀
√ ( T/μ) = λf
√ ) 2T₀/μ = λ f
√ 2 √ T₀/μ = λ f
substituimos
√2 ( λ₀ f₀) = λ f
si suponemos que en los dos caso la cuerda este en el mismo armónico fundamental, esto es que la longitud de onda unicamente depende de la longitud de la cuerda, la cual no cambia
λ₀ = λ
f = f₀ √2
f = 435 √2
f = 615,2 Hz
b) La tension se reduce a la mitad
T = T₀/2
RA ( T₀/2μ) = λ f
Ra(T₀/μ) 1/ra 2 = λ f
fo /√ 2 = f
f = 435/√2
f = 307,6 Hz
Divide the force given by mass and you will find the acceleration of the object :-
F = m × a
3.63 = 18.15 × a
3.63 = 18.15a
a = 3.63/18.15
a = 0.2 m/s^2
hope it helps!
