Answer:
a 15.22 m/s
b 45.65 m
Explanation:
Using the same formula,
x = vt, where
x is now 45.65, and
t is 3 s, then
45.65 = 3v
v = 45.65/3
v = 15.22 m/s
See the attachment for the part b. We used the distance gotten in part B, to find question A
A constant power is supplied to a rotating disc .the relationship of angular velocity of disc and number of rotations made by th
1 answer:
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Answer:
e. Not enough information to determine
Explanation:
This question is incomplete. Here is the complete question with my solution afterwards;
A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turntable (initially at rest) begins to rotate with its rate of rotation constantly increasing.
What is the first event that will occur?(Assume non-zero frictional force and the same coefficients of friction for both bugs.)
a. The ladybug begins to slide
b. The gentleman bug begins to slide
c. Both bugs begin to slide at the same time
d. Nothing ever happens
e. Not enough information to determine
The centripetal force acting on a rotating body or bugs can be written as,
mass of the corresponding bugs
corresponding radial distance of each bug
angular speed of the turntable
The centripetal force tries to slide the bugs in an outward direction and it is directly proportional to the products of its mass and radial distance from the axis of rotation of the turntable
∝
Since the radial distance from the axis of rotation of the turntable for each bug is given, but the mass is not given, the given information is therefore not enough to determine which bugs will slide first.
Option "e" is correct.
Answer:
The newton’s second law is F=ma
The Gravitational force is
Explanation:
Given that,
The equivalent formulas for velocity, acceleration, and force using the relationships covered for UCM, Newton’s Laws, and Gravitation.
We know that,
Velocity :
The velocity is equal to the rate of position of the object.
....(I)
Acceleration :
The acceleration is equal to the rate of velocity of the object.
....(II)
Newton’s second Laws
The force is equal to the change in momentum.
In mathematically,
Put the value of p
Put the value from equation (II)
This is newton’s second laws.
Gravitational force :
The force is equal to the product of mass of objects and divided by square of distance.
In mathematically,
Where, m₁₂ = mass of first object
m= mass of second object
r = distance between both objects
Hence, The newton’s second law is F=ma
The Gravitational force is
Complete Question
The complete question is shown on the first uploaded image
Answer:
Force on each hand is 196.22 N
Force on each foot is 95.8 N
Explanation:
In order to get a better understanding of this question let us explain some concepts
Normal Force:
We can define normal force Fn as that type of force which makes a 90 degree angle with the surface on which it is exerted.
Torque:
We can define torque as the moment of forces that tends to produce or cause rotation
From the question we are given that
Weight of body is (W) = 584 N
The normal force on both hands (Ha) = ?
The normal force on both legs (Lg) = ?
Looking at the diagram the person is at equilibrium so
584 = Ha + Lg
an also this mean that torques acting on the body is balanced
So, 0.410 Ha = 0.840 Lg
Making Lg the subject of formula in the equation above we
Lg = 0.4881 Ha
Considering the first equation and replacing Lg with this recent equation we have
584 = Ha + 0.4881 Ha
Therefore Ha = 392.44 N
This value obtained is for both hands for each hand we divide by 2
Therefore we have for each hand =196.55 N
Since we have been able to get the force on both hands we can substitute it in to the equation where we made Lg the subject of formula and we have
Lg = 0.4881 × 392.44
= 191.22 N
The value above is the force on both legs to obtain the force on each leg we have
191.22/2 = 95.8 N.
