the container is filled with liquid. the depth of liquid is 60 cm. if it is exerting the pressure of 2000pa. calculate the densi
1 answer:
Answer:
Explanation:
Given that,
A container is filled with liquid. At a depth of 60 cm it exerts a pressure of 2000 Pa.
We need to find the density of the liquid.
The pressure exerted by liquid at a depth is given by the formula as follows :
h = 60 cm = 0.6 m
g is acceleration due to gravity
Putting all the values,
So, the density of the liquid is .
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Answer:
1) Charge chord resistance is 75 Ω
2) Charge chord resistance is 6.33 Ω
Explanation:
1) To answer the question, we note that the the formula voltage is found as follows;
V = IR
Therefore,
2) Where the voltage, V = 19.5 V and the current, I = 3.33 A, we have;
Initial resistance R₁ = 19.5 V/(3.33 A) = 5.86 Ω
However, to reduce the current to 1.6 A, we have;
Therefore, where the resistance is found by the sum of the total resistance we have;
= R₁ + Charge chord resistance
∴ 12.1875 = 5.86 + Charge chord resistance
Hence, charge chord resistance = 6.33 Ω
Answer:
Explanation:
The general equation for position of Simple harmonic motion is given as:
........(1)
where,
x = Position of the wave
A = Amplitude of the wave
ω = Angular velocity
t = time
In this case, the amplitude is just half the range,
thus,
(Given range = 3cm)
A = 1.5 cm
Now, The angular velocity is given as:
Where, T = time period of the wave =0.27s (given)
or
so, at time t = 55 s, the equation (1) becomes as:
on solving the above equation we get,
here the negative sign depicts the position in the opposite direction of +x
Actually Welcome to the concept of Efficiency.
Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%
The efficiency is => 22% => 22/100.
so we get as,
E = W(output) /W(input)
hence, W(output) = E x W(input)
so we get as,
W(output) = (22/100) x 2.2 x 10^7
=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7
hence, W(output) = 4.84 x 10^6 J
The useful work done on the mass is 4.84 x 10^6 J