Answer:
1.05 N
Explanation:
K = 0.7 N/m
e = 1.5 m
F = ?
from Hooke's law of elasticity
F = Ke
= 0.7×1.5
= 1.05 N
Answer:
a) Fₓ = 23.5 N
b) Net force = Fₓ
Explanation:
An image of the question as described is attached to this solution.
From the image attached, the forces acting on the box include the weight of the box, the normal reaction of the surface on the box, the applied force on the box and the Frictional force opposing the motion of the box (which is negligible and equal to 0)
a) From the diagram, the horizontal component of the force is
Fₓ = 25 cos 20° = 23.49 N = 25 N
b) Again, from the diagram attached, doing a force balance on the box, in the horizontal direction, we obtain
Net force = Fₓ - Frictional force
But frictional force is 0 N
Net force = Fₓ
Hope this Helps!!!
Answer:
E = 1.25×10¹³ N/m²
Explanation:
Young's modulus is defined as:
E = stress / strain
E = (F / A) / (dL / L)
E = (F L) / (A dL)
Given:
F = 10 kg × 9.8 m/s² = 98 N
L = 1 m
dL = 10⁻⁵ m
A = π/4 (0.001 m)² = 7.85×10⁻⁷ m²
Solve:
E = (98 N × 1 m) / (7.85×10⁻⁷ m² × 10⁻⁵ m)
E = 1.25×10¹³ N/m²
Round as needed.
Answer:
1.17894 m
Explanation:
The rock is at one end of the rod which is 0.211 m from the fulcrum
F = Force
d = Distance
L = Length of rod
M = Mass of rock = 325 kg
g = Acceleration due to gravity = 9.81 m/s²
Torque

Torque of man

Torque of rock

The torques acting on the system is conserved

The length of the rod is 1.17894 m
Answer:
0.006 m
Explanation:
d = separation between the slits = 0.150 mm = 0.150 x 10⁻³ m
λ = wavelength of the light = 643 nm = 643 x 10⁻⁹ m
D = distance of the screen where interference pattern is observed = 140 cm = 1.40 m
δ = Path difference
Path difference is given as
δ = Dλ/d
δ = (1.40) (643 x 10⁻⁹)/(0.150 x 10⁻³)
δ = 0.006 m