Answer:
The magnitude of the force is F= 3072.9 N.
Explanation:
The expression for the power in terms of force and velocity is as follows;
P=Fv
Here, P is the power, F is the force and v is the velocity.
Rearrange the above expression to get the value of the force.
Convert power from horsepower to watt.
P=75.0 hp
P= (75)(745.7) W
P= 55,927.5 W
Put P= 55,927.5 W and v= 18.2 meter per second in the above expression.
F= 3072.9 N
Therefore, the magnitude of the force is F= 3072.9 N.
Answer:
P =105.44 W
Explanation:
Given that
D= 10 cm ,L= 60 cm
d= 0.1 cm ,B= 6.4 mT
ρ= 1.7 x 10⁻⁸ Ω · m
The number of turns N
N= L/d
N= 60/0.1 = 600 turns
Length of wire
Lc= πDN
Lc= 3.14 x 0.1 x 600
Lc=188.4 m
The magnetic filed given as
Now by putting the values
I=5.09 A
The resistance R given as
R=4.07 Ω
Power P
p =I²R
P= 5.09² x 4.07 W
P =105.44 W
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
Answer:
2 x 10⁻³ volts
Explanation:
B = magnetic of magnetic field parallel to the axis of loop = 1 T
= rate of change of area of the loop = 20 cm²/s = 20 x 10⁻⁴ m²
θ = Angle of the magnetic field with the area vector = 0
E = emf induced in the loop
Induced emf is given as
E = B
E = (1) (20 x 10⁻⁴ )
E = 2 x 10⁻³ volts
E = 2 mV