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ankoles [38]
2 years ago
13

A car needs to generate 75.0 hp in order to maintain a constant velocity of 18.2 m/s on a flat road. What is the magnitude of th

e total resistive force acting on the car (due to friction, air resistance, etc.)
Physics
1 answer:
stiks02 [169]2 years ago
3 0

Answer:

The magnitude of the force is F= 3072.9 N.

Explanation:

The expression for the power in terms of force and velocity is as follows;

P=Fv

Here, P is the power, F is the force and v is the velocity.

Rearrange the above expression to get the value of the force.

F=\frac{P}{v}

Convert power from horsepower to watt.

P=75.0 hp

P= (75)(745.7) W

P= 55,927.5 W

Put P= 55,927.5 W and v= 18.2 meter per second in the above expression.

F=\frac{55,927.5}{18.2}

F= 3072.9 N

Therefore, the magnitude of the force is F= 3072.9 N.

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When block is pushed upwards along the inclined plane

the net force applied on the block will be given as

F_{net} = mg sin\theta + \mu_k mg cos\theta

here we know that

m = 75 kg

\theta = 8.5 degree

\mu_k = 0.16

now plug in all values into this

F_{net} = 75\times 9.8 sin8.5 + 0.16 \times 75\times 9.8 cos8.5

F = 225 N

now for finding the power is given as

P = Fv

0.87 \times 10^3 = 225 \time v

v = \frac{870}{225} = 3.87 m/s

6 0
1 year ago
For each of the following systems and time intervals, select the appropriate version of
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The heating coils in you toaster during the first five seconds after you turn the toaster on is Δ K = W + Q.


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your home during five minutes of a sunny afternoon while the temperature in the home remains fixed is ΔU = W + Q + TMW + TMT</span>  

 

 

4 0
2 years ago
A 72 kg skydiver is descending on a parachute. His speed is still increasing at 1.2 m/s2. What are the magnitude and direction o
frozen [14]

Answer:

86.4 N downward

Explanation:

Force: This can be defined as the product of mass and acceleration of a body.

The S.I unit of Force is Newton(N).

The Expression of force is given as,

F = ma ................ Equation 1

Where F = force of the parachute harness, m = mass of the skydiver, a = acceleration of the skydiver.

Given: m = 72 kg, a = 1.2 m/s²

Substitute into equation 1

F = 72(1.2)

F = 86.4 N down ward.

Hence the force on the parachute harness = 86.4 N downward

8 0
2 years ago
A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the partic
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<span>v =Integral(F/m)dtv=Integral(F/m)dt =â«50(6t2â’4t+3)/5dt=â«05(6t2â’4t+3)/5dt =1/5â—(2t3â’2t2+3t)|(0,5)=1/5â—(2t3â’2t2+3t)|(0,5) =1/5â—(250â’50+15)=1/5â—(250â’50+15) =215/5=215/5 =43m/s.</span>
6 0
2 years ago
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the correct answer is 27 hours per week :) hope this helps


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