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Svetach [21]
2 years ago
12

How does increasing the distance between charged objects affect the electric force between them? the electric force increases be

cause the distance has an indirect relationship to the force. the electric force increases because the distance has a direct relationship to the force. the electric force decreases because the distance has an indirect relationship to the force. the electric force decreases because the distance has a direct relationship to the force.
Physics
2 answers:
weqwewe [10]2 years ago
6 0
According to Columb's law, when the distance between charged objects is increased then the electric force between them will decrease, this is because the two terms are inversely related. the correct option is C.
konstantin123 [22]2 years ago
3 0

the electric force decreases because the distance has an indirect relationship to the force

Explanation:

The electric force between two objects is given by

F=k \frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the distance between the two objects

As we can see from the formula, the magnitude of the force is inversely proportional to the square of the distance: so, when the distance between the object increases, the magnitude of the force decreases.

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What is the efficiency of a machine if your work on the machine is 1200 j and the machines output work is 300 j?
inysia [295]

Answer:

The efificiency is 0,25 of the machine  (25%). See the explanation below

Explanation:

We calculate the efficiency with this formula:

Efficiency = energy obtained/energy supplied= 300 Joule/1200 Joule

Efficiency= 0,25

Efficiency(%) = 0,25 x100 = 25%

7 0
2 years ago
Read 2 more answers
A particle moves along a straight line with a velocity in meters per second given by v = 12 - 3t + 8t, where t is in seconds. Wh
elena-14-01-66 [18.8K]

Answer:

Explanation:

Given the velocity of a particle modeled by the equation

v = 13-3t+8t² where t is in seconds

Given t = 0 and position s = +5m

A) To get the position as a function of time, we will integrate the function with respect to t ad shown;

v = 13-3t+8t²

S = ∫13-3t+8t² dt

S = 13t-13t²/2+8t³/3 + C

at t = 0 and S = +5m

5 = 13(0)-13(0)²/2+8(0)³/3+C

5 = 0-0+0+C

C = 5

Substituting c = 5 into the displacement function

S = 13t-13t²/2+8t³/3 + C

S = 13t-13t²/2+8t³/3 + 5

B) acceleration is the change in velocity with respect to time.

a = dv/dt

Given v = 13-3t+8t²

a= dv/dt = -3+16t

a = 16-3t

C) acceleration at t = 6s is derived by plugging in t = 6 into the resulting equations in (B)

a = 16-3t

a = 16-3(6)

a = 16-18

a = -2m/s²

D) net displacement from t = 0 to t = 6s

At t = 0:

S(0) = 13(0)-13(0)²/2+8(0)³/3 + 5

S(0) = 0+5

S(0) = 5m

At t = 6s

S(6) = 13(6)-13(6)²/2+8(6)³/3 + 5

S(6) = 78-234+576+5

S(6) = 425m

Net displacement from t = 0s to t = 6s is s(6)-s(0)

= 425-5

= 420m

E) Total distance travelled D = S(6)+S(0)

= 425+5

= 430m

F) Average velocity = ∆S/∆t

Average velocity = S(6)-S(0)/6-0

Average velocity = 425-5/6

Average velocity = 420/6

Average velocity = 70m/s

4 0
2 years ago
Which statement correctly describes the relationship between frequency and wavelength?
Len [333]
The relationship between the frequency and wavelength of a wave is given by the equation:

v=λf, where v is the velocity of the wave, λ is the wavelength and f is the frequency. 

If we divide the equation by f we get:

λ=v/f

From here we see that the wavelength and frequency are inversely proportional. So as the frequency increases the wavelength decreases. 

So the second statement is true: As the frequency of a wave increases, the shorter the wavelength is.  
3 0
2 years ago
Read 2 more answers
Point m is located a distance 2d from the midpoint between the two wires. find the magnitude of the magnetic field b1m created a
Tema [17]

Note: The diagram referred to in the question is attached here as a file.

Answer:

The magnitude of the magnetic field is B = \frac{0.071 \mu I}{d}

Explanation:

The magnetic field can be determined by the relationship:

B = \frac{\mu I}{2\pi R}...............(1)

Were I is the current flowing through the wires

The distance R from point 1 to m is calculated using the pythagora's theorem

R = \sqrt{d^{2} + (2d)^{2}  }

R = \sqrt{5d^{2} } \\R = d\sqrt{5}

Substituting R into equation (1)

B = \frac{\mu I}{2\pi d\sqrt{5} }

B = \frac{0.071 \mu I}{d}

3 0
2 years ago
A car of mass 1100kg moves at 24 m/s. What is the braking force needed to bring the car to a halt in 2.0 seconds? N
LenaWriter [7]

13200N

Explanation:

Given parameters:

Mass = 1100kg

Velocity = 24m/s

time = 2s

unknown:

Braking force = ?

Solution:

The braking force is the force needed to stop the car from moving.

   Force  =  ma = \frac{mv}{t}

  m is the mass of the car

  v is the velocity

  t is the time taken

  Force = \frac{1100 x 24}{2} = 13200N

Learn more:

Force brainly.com/question/4033012

#learnwithBrainly

8 0
2 years ago
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