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2 years ago

Select the volume units that are greater than one liter.

2 answers:

4 0

The base units of length and volume are linked in the metric system. By definition, a liter is equal to the volume of a cube exactly 10 cm tall, 10 cm long, and 10 cm wide. Because the volume of this cube is 1000 cubic centimeters and a liter contains 1000 milliliters, 1 milliliter is equivalent to 1 cubic centimeter.

Marat540 [252]2 years ago

3 0

Dekaliter is 10 times bigger than 1 liter.
1 Dekalite = 10 Liters

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What is the minimum work needed to push a 950-kg car 710 m up along a 9.0Â° incline? ignore friction?

kakasveta [241]

1.0344645 MJ The minimum energy need is the potential energy of the car at the top of the ramp and is given by mass*gravity*height mass is known, gravity is assumed to be 9.81m/s^2 as it is on earth, and height must be calculated using trigonometry. height=sin(9 degrees)*710m=111meters so potential energy = 950kg*111m*9.81m/s^2=1.0344645 MJ Using the law of the conservation of energy we can assume that the energy expended to push the car up the incline was at least the potential energy gained by moving 111m against the pull of gravity.

7 0

2 years ago

Read 2 more answers

A helicopter (m = 3250 kg) is cruising at a speed of 56.9 m/s atan altitude of 185 m. What is the total mechanical energy of the

taurus [48]

Answer:

The mechanical energy of the helicopter is $1.12\times 10^7\ J$ .

Explanation:

It is given that,

Mass of the helicopter, m = 3250 kg

Speed of the helicopter, v = 56.9 m/s

Position of the helicopter, h = 185 m

The energy possessed by an object due to its motion is called its kinetic energy. It is given by :

$E=\dfrac{1}{2}mv^2$

$E=\dfrac{1}{2}\times 3250\times (56.9)^2$

$E=5.26\times 10^6\ J$

The energy possessed by an object due to its position is called its potential energy. It is given by :

$E=mgh$

$E=3250\times 9.8\times 185$

$E=5.89\times 10^6\ J$

The sum of kinetic and potential energy is called mechanical energy of the system. It is given by :

$M=5.26\times 10^6+5.89\times 10^6$

$M=11.15\times 10^6\ J$

$M=1.12\times 10^7\ J$

So, the mechanical energy of the helicopter is $1.12\times 10^7\ J$ . Hence, this is the required solution.

6 0

2 years ago

A long, thin straight wire with linear charge density λ runs down the center of a thin, hollow metal cylinder of radius R. The c

netineya [11]

Answer:

$E=\frac{\lambda}{2\pi r\epsilon_0}$

Explanation:

We are given that

Linear charge density of wire= $\lambda$

Radius of hollow cylinder=R

Net linear charge density of cylinder= $2\lambda$

We have to find the expression for the magnitude of the electric field strength inside the cylinder r<R

By Gauss theorem

$\oint E.dS=\frac{q}{\epsilon_0}$

$q=\lambda L$

$E(2\pi rL)=\frac{L\lambda}{\epsilon_0}$

Where surface area of cylinder= $2\pi rL$

$E=\frac{\lambda}{2\pi r\epsilon_0}$

8 0

2 years ago

Which of the following statements are true for electric field lines? Check all that apply. Check all that apply. Electric field

Scilla [17]

Answer:

Electric field lines point away from positive charges and toward negative charges. True

Electric field lines are continuous; they do not have a beginning or an ending. False

Electric field lines can never intersect. True

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. False

At every point in space, the electric field vector at that point is tangent to the electric field line through that point. True

Explanation:

Electric field lines point away from positive charges and toward negative charges. Always the field lines go to negative charges and leave from positive charges.

Electric field lines are continuous; they do not have a beginning or an ending. False

Because the field lines starts at positive charges and ends in negative charges.

Electric field lines can never intersect. True

It can not intercept the field lines because in that point the the field would have two directions. Besides, in that point the real value of the field should be found adding both field lines.

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. False

This fact is opposite to that so the regions of space where the magnitude the electric field is weak the lines are father apart and where the field is strong the lines are close together.

At every point in space, the electric field vector at that point is tangent to the electric field line through that point. True

This statement correspond to the definition of the field line.

5 0

2 years ago

A 2.00-kg block of aluminum at 50.0 °C is dropped into 5.00 kg of water at 20.0 °C. What is the change in entropy during the app

lesya692 [45]

Given:

$m_{1} = 2000gm$