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suter [353]
1 year ago
13

A vertical wire carries current in the upward direction. An electron is traveling parallel to the wire. What is the angle ααalph

a between the velocity of the electron and the magnetic field of the wire? Express your answer in degrees. View Available Hint(s) ααalpha = nothing degreesdegrees
Physics
1 answer:
Katen [24]1 year ago
5 0

Answer:

First of all note that The magnetic field produced by the vertical wire will be into on the right hand side and it will be out of the page on the left hand side

Assuming that the electron beam is coming from the right hand side of the page parallel to the wire, The direction of the velocity vector(V) is left and the direction of magnetic field due the wire(B) is into the page. If u use right hand rule, you will get the direction downwards but as the formula also depends on q , the charge on electron is negative .Therefore the direction will be inverted i.e Upwards.

If you assume the electron beam coming from left hand side.Then also u will get the same answer.

So, the angle α between the velocity of the electron and the magnetic field of the wire is 90°.

Explanation:

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Answer:

Explanation:

Force of friction at car B ( break was applied by car B ) =μ mg = .65 x  2100 X 9.8  = 13377 N .

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kinetic energy of both the cars = 1/2 ( 2100 + 1500 ) x v²

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so , applying work - energy theory ,

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v² = 54.25

v = 7.365 m /s

This is the common velocity of both the cars .

To know the speed of car A , we shall apply law of conservation of momentum  .Let the speed of car A before collision be v₁ .

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1500 x v₁ = ( 1500 + 2100 ) x 7.365

v₁ = 17.676 m /s

= 63.63 mph .

( b )

yes Car A was crossing speed limit by a difference of

63.63 - 35 = 28.63 mph.

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2 years ago
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dolphi86 [110]

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Explanation:

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