Answer:
Order of maximum transmission of the polarizer is A, C and B.
Solution:
As per the question:
For the first polarizer, the angle is quite insignificant:
(A) 
:
The light intensity after passing through the first polarizer is 
and this intensity does not depend on the angle of the polarizer.
Consider with the vertical, the intensity is given by:
(B) 
:
Suppose the second polarizer is 
with the vertical.
Now, intensity through the second polarizer:
Now, if we consider the second polarizer to be ,
(C) 
:
Now,
Intensity through the third polarizer, if it is with the vertical:
The elastic potential energy of the spring is 6.8 J
Explanation:
The elastic potential energy of a compressed/stretched spring is given by the equation:
where
k is the spring constant
x is the elongation of the spring
The spring constant of the spring in this problem can be found by keeping in mind the relationship between force (F) and elongation (x) (Hooke's law):
By looking at the graph and comparing it with the formula, we realize that the slope of the force-elongation graph corresponds to the spring constant. Therefore in this case,
Therefore when the spring has a elongation of 
, its potential energy is
Learn more about potential energy:
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Answer:
The two correct answers are B.) reacting quickly with water, and D.) forming bonds with other atoms.
Explanation:
Answer:
C. At maximum displacement, its instantaneous acceleration is also at maximum.
Explanation:
Lets take
The general equation of the SHM
Displacement
x= A sinω t
velocity
V= Aω cosω t
Acceleration
a= -Aω² sinω t
Form the above we can say that displacement and the acceleration are in the same phase.
Therefore when displacement is maximum then acceleration also will be maximum.
Therefore the answer is C.
A. The proeutectoid phase is Fe₃c because 0.95 wt/c is greater than the eutectoid composition which is 0.76 wt/c
b. We determine how much total territe and cementite form, we apply the lever rule expressions yields.
Wx = (fe₃c-co/cfe₃ c-cx = 6.70- 0.95/6.70- 0.022 = 0.86
The total cementite
Wfe₃C = 10-Cx/ Cfe₃c -Cx = 0.95 - 0.022/6.70 - 0.022 = 0.14
The total cementite which is formed is
(0.14) × (3.5kg) = 0.49kg
c. We calculate the pearule and the procutectoid phase which cementite form the equation
Ci = 0.95 wt/c
Wp = 6.70 -ci/6.70 - 0.76 = 6.70 -0.95/6.70 - 0.76 = 0.97
0.97 corresponds to mass.
W fe₃ C¹ = Ci - 0.76/5.94 = 0.03
∴ It is equivalent to
(0.03) × (3.5) = 0.11kg of total of 3.5kg mass.
