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Artist 52 [7]
2 years ago
13

A 8.00g sample of substance (substance, molar mass = 152.0 g/mol) was combusted in a bomb calorimeter with a heat capacity of 6.

21 kJ/°C. If the temperature rose from 25.0°C to 75.0°C, determine the value of ΔH°comb for substance.
Physics
1 answer:
aleksandrvk [35]2 years ago
4 0

Answer:

ΔH°comb=-5899.5 kJ/mol

Explanation:

First, consider the energy balance:

m_{c} *Cp*(T_{2}-T_{1})=-n_{s} *H_{c} Where m_{c} is the calorimeter mass and n_{s} is the number of moles of the samples; H_{c} is the combustion enthalpy. The energy balance says that the energy that the reaction release is employed in rise the temperature of the calorimeter, which is designed to be adiabatic, so it is suppose that the total energy is employed rising the calorimeter temperature.

The product m_{c} *Cp is the heat capacity, so the balance equation is:

6.21\frac{kJ}{K}*(75-25)=-8.00g*\frac{mol}{152.0g}*H_{c}

So, the enthalpy of combustion can be calculated:

H_{c}=-5899.5\frac{kJ}{mol}

I will be happy to solve any doubt you have.

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2 years ago
Water runs into a fountain, filling all the pipes, at a steady rate of 0.750 m3>s. (a) How fast will it shoot out of a hole 4
kati45 [8]

Answer:

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solution

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0.750 = \frac{\pi }{4} × (4.50×10^{-2})²  × velocity

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velocity  = 472 m/s

and

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2 years ago
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vfiekz [6]
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6 0
2 years ago
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Answer:

1.38*10^18 kg

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7 0
2 years ago
When 30 V is applied across a resistor it generates 600 W of heat: what is the magnitude of its resistance?
grandymaker [24]

Answer:

<h2>1.5 ohms</h2>

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3 0
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