answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ikadub [295]
2 years ago
5

Solar wind particles can be captured by the Earth's magnetosphere. When these particles spiral down along the magnetic field int

o the atmosphere, they are responsible for ?
Physics
1 answer:
Alex73 [517]2 years ago
5 0

Answer:

Solar wind particles can be captured by the Earth's magnetosphere. When these particles spiral down along the magnetic field into the atmosphere, they are responsible for?

Answer is Aurorae.

Explanation:

Solar Wind:

A planet's magnetic filed forms a shield to protect the surface of planet from energetic and charged particles coming from sun and other planets. The sun is continuously  sending out charged particles , called Solar wind.

Magnetosphere of planet:

If a planet has a magnetic field then it will interact with the solar wind and deflect the charged particles in the wind. Due to which an elongated cavity in solar wind formed. This cavity is called magnetosphere of the planet.

When Solar wind particles run in a magnetic field , they are  deflected and spiral down along magnetic field lines into the atmosphere.

Most of the solar wind particles deflected around the planet but a few particles manage to leak into the magnetic filed and become trapped in the magnetic field of the planet, to create Radiation Belts or Charged Particles Belts.

Variable Solar Wind can give some radiation belt particles with enough energy to spiral down along the magnetic filed into the atmosphere and Create Aurorae

Here Aurorae is an atmospheric phenomenon consisting of Bands, streamers of light, usually yellow , green or red , that move across the sky in the polar regions.

 

You might be interested in
Miners find a rock that was formed from magma deep underground what type of rock could it be
andreyandreev [35.5K]
It can be an igneous rock
3 0
2 years ago
A truck collides with a car on horizontal ground. At one moment during the collision, the magnitude of the acceleration of the t
Mice21 [21]

Answer:

The magnitude of the acceleration of the car is 35.53 m/s²

Explanation:

Given;

acceleration of the truck, a_t = 12.7 m/s²

mass of the truck, m_t = 2490 kg

mass of the car, m_c = 890 kg

let the acceleration of the car at the moment they collided = a_c

Apply Newton's third law of motion;

Magnitude of force exerted by the truck = Magnitude of force exerted by the car.

The force exerted by the car occurs in the opposite direction.

F_c = -F_t\\\\m_ca_c = -m_t a_t\\\\a_c =- \frac{m_ta_t}{m_c} \\\\a_c = -\frac{2490 \times 12.7}{890} \\\\a_c = - 35.53 \ m/s^2

Therefore, the magnitude of the acceleration of the car is 35.53 m/s²

3 0
2 years ago
Driving your Ferrari through the Italian countryside at a speedy 88 m/s, you approach an opera diva singing a high C (1,046 Hz).
MrRissso [65]

Answer:

You will hear the note E₆

Explanation:

We know that:

Your speed = 88m/s

Original frequency = 1,046 Hz

Sound speed = 340 m/s

The Doppler effect says that:

f' = \frac{v \pm v0 }{v \mp vs}*f

Where:

f = original frequency

f' = new frequency

v = velocity of the sound wave

v0 = your velocity

vs = velocity of the source, in this case, the source is the diva, we assume that she does not move, so vs = 0.

Replacing the values that we know in the equation we have:

f' = \frac{340 m/s + 88m/s}{340 m/s} *1,046 Hz = 1,316.73 Hz

This frequency is close to the note E₆ (1,318.5 Hz)

7 0
1 year ago
Haley noticed a small spot on her skin that turned out to be skin cancer. Which treatment is her doctor most likely to use?
vova2212 [387]

Answer:

Radiation therapy

Explanation:

Her doctor is more likely to use radiation therapy to irradiate the cancerous cells on the skin. The doctor uses soft x-rays to kill the cancer cells. The therapy is used even after surgery as it has the advantage of delaying the advancement of future cancers.

6 0
2 years ago
Sunlight strikes a piece of crown glass at an angle of incidence of 38.0°. Calculate the difference in the angle of refraction b
zhuklara [117]

Answer:

Difference in the angle of refraction = 0.3°

41.04° is the minimum angle of incidence.

Explanation:

Angle of incidence  = 38.0°

For yellow light :

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₁ is the refractive index for yellow light which is 1.523

n₂ is the refractive index of air which is 1

So,  

\frac {sin\theta_2}{sin{38.0}^0}=\frac {1.523}{1}

{sin\theta_2}=0.9377

Angle of refraction for yellow light = sin⁻¹ 0.9377 = 69.67°.

For green light :

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₁ is the refractive index for green light which is 1.526

n₂ is the refractive index of air which is 1

So,  

\frac {sin\theta_2}{sin{38.0}^0}=\frac {1.526}{1}

{sin\theta_2}=0.9395

Angle of refraction for green light = sin⁻¹ 0.9395 = 69.97°.

The difference in the angle of refraction = 69.97° - 69.67° = 0.3°

Calculation of the critical angle for the yellow light for the total internal reflection to occur :

The formula for the critical angle is:

{sin\theta_{critical}}=\frac {n_r}{n_i}

Where,  

{\theta_{critical}} is the critical angle

n_r is the refractive index of the refractive medium.

n_i is the refractive index of the incident medium.

n₁ is the refractive index for yellow light which is 1.523 (incident medium)  

n₂ is the refractive index of air which is 1 (refractive medium)

Applying in the formula as:

{sin\theta_{critical}}=\frac {1}{1.523}

The critical angle is = sin⁻¹ 0.6566 = 41.04°

5 0
2 years ago
Other questions:
  • Make a diagram showing the forces acting on a coasting bike rider traveling at 25km/h on a flat roadway.
    14·2 answers
  • What is true of an object pulled inward in an electric field?
    9·1 answer
  • A pendulum is used in a large clock. The pendulum has a mass of 2kg. If the pendulum is moving at a speed of 2.9 m/s when it rea
    12·2 answers
  • Suppose 1 kg of Hydrogen is converted into Helium. a) What is the mass of the He produced? b) How much energy is released in thi
    11·2 answers
  • Whose research showed that atoms consist of small positively charged nuclear centers and lots of empty space populated by electr
    13·1 answer
  • A roadway for stunt drivers is designed for racecars moving at a speed of 40 m/s. A curved section of the roadway is a circular
    6·1 answer
  • A very long conducting tube (hollow cylinder) has inner radius a and outer radius b. It carries charge per unit length +α, where
    15·1 answer
  • If I0 is the intensity of the unpolarized light incident on the first polarizer, and I1 and I2 denote the intensity of the light
    14·1 answer
  • If a sound with frequency fs is produced by a source traveling along a line with speed vs. If an observer is traveling with spee
    13·1 answer
  • Packages having a mass of 6 kgkg slide down a smooth chute and land horizontally with a speed of 3 m/sm/s on the surface of a co
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!