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nydimaria [60]
2 years ago
12

A high-speed dart is shot from ground level with a speed of 150 m/s at an angle 30° above the horizontal. What is the vertical c

omponent of its velocity after 4.0 s if air resistance is neglected?
Physics
1 answer:
FinnZ [79.3K]2 years ago
6 0
<h2>This vertical component of velocity is 35 m/s </h2>

Explanation:

The dart is project with 150 m/s from a point at an angle of 30⁰

The vertical component of velocity = 150 sin 30 = 75 m/s

Thus initial vertical velocity is = 75 m/s

The velocity after 4 s can be calculate by

v = u - g t

here u is the initial velocity and t is the time , g is the acceleration due to gravity .

Thus v = 75 - 10 x 4 = 35 m/s

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Noise-canceling headphones are an application of destructive interference. Each side of the headphones uses a microphone to pick
jeka57 [31]

Answer:

2.5 ms

Explanation:

v = Speed of sound in air = 343 m/s

f = Frequency = 200 Hz

Wavelength is given by

\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{343}{200}\\\Rightarrow \lambda=1.715\ m

In the case of destructive interference, path difference is given by

x=\dfrac{\lambda}{2}\\\Rightarrow x=\dfrac{1.715}{2}\\\Rightarrow x=0.8575\ m

Delay is givenn by

t=\dfrac{x}{v}\\\Rightarrow t=\dfrac{0.8575}{343}\\\Rightarrow t=0.0025\ s

The minimum headphone delay, that will cancel this noise is 2.5 ms

6 0
2 years ago
Charge q1 is distance r from a positive point charge Q. Charge q2=q1/3 is distance 2r from Q. What is the ratio U1/U2 of their p
worty [1.4K]

We have that The ratio U1/U2 of their potential energies due to their interactions with Q is

  • U1/U2=6
  • U1/U2=6

From the question we are told that

Question 1

Charge q1 is distance r from a positive point charge Q.

Question 2

Charge q2=q1/3 is distance 2r from Q.

Charge q1 is distance s from the negative plate of a parallel-plate capacitor.

Charge q2=q1/3 is distance 2s from the negative plate.

Generally the equation for the potential energy  is mathematically given as

U=\frac{-k*qQ}{r}

Therefore

The Equations of U1 and U2 is

For U1

U1=\frac{-k*q_1Q}{r}

For U2

U2=\frac{-k*q_1Q}{3*2r}

Since

U is a function of q and  q2=q1/3

Therefore

U1/U2=6

For Question 2

For U1

U1=\frac{-k*q_1Q}{s}\\\\For U2\\\\U2=\frac{-k*q_1Q}{3*2r}

Therefore

U1/U2=6

For more information on this visit

brainly.com/question/23379286?referrer=searchResults

7 0
2 years ago
A more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a consta
-Dominant- [34]

The car would go from  zero to 58.0 mph in 2.6 sec.

Since the force on the car is constant, therefore the acceleration of the car would also be constant.

Now for constant acceleration we can use the equation of motion

Using first equation of motion to calculate the acceleration of the car

v=u+at

29=0+a×1.30       ...... Eq. (1)

Again using the first equation of motion

58=0+a*t             ....... Eq. (2)

Dividing eq. (2) with equation 1

t=2×1.3

t=2.6 sec

7 0
2 years ago
Consider two circular metal wire loops each carrying the same current I as shown below. In what r... Consider two circular metal
NeX [460]

Answer:

1) The magnetic field outside the loop is zero.

In region III the magnetic fields due to the two wire loops point in the opposite direction andhence cancel each other. Therefore the magnetic field is zero in region I, III and V

The diagram is attached

6 0
2 years ago
During metamorphism, what is the major effect of chemically active fluids?
xz_007 [3.2K]

Answer:

Option b

Explanation:

Metamorphism is the process where the variation of the geological texture resulting from the different arrangement of the minerals or the variation of minerals in protoliths, i.e., pre- existing rocks take place such that there occurs no change in state of the protolith, i.e., it does not melt into magma.

The change takes place as a result of the presence of chemically active fluids, heat and pressure.

There is a reaction between the chemically active fluid and the rock through which it passes and promotes the movement of the dissolved ions of silicate and promotes the growth of the mineral grains.

7 0
2 years ago
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