Answer:
Explanation:
Momentum is the product of mass of a body and its velocity.
Given the mass of the puck m1 = 0.16kg
velocity of the puck v1 = 40m/s
Given the mass of the goalkeeper m2 = 120kg
velocity of the goalkeeper v2= 0m/s (goal keeper at rest)
The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is expressed as:
m1v1 + m2v2 (their momentum will be added since they collide)
= 0.16(40) + 120(0)
= 0.16(40) + 0
= 6.4kgm/s
Let us calculate their common velocity using the conservation of momentum formula;
m1u1 + m2u2 = (m1+m2)v
6.4 = (0.16+120)v
6.4 = 120.16v
v = 6.4/120.16
v = 0.053m/s
Hence after collision, both objects move at a velocity of 0.053m/s
Momentum of the puck after collision = m1v
Momentum of the puck after collision = 0.16*0.053m/s
Momentum of the puck after collision = 0.0085kgm/s
Momentum of the keeper after collision = m2v
Momentum of the keeper after collision = 120*0.053m/s
Momentum of the keeper after collision = 6.36kgm/s
From the calculation above, it can be seen that the keeper has the greater momentum after the puck was caught since the momentum of the keeper after collision is greater than that of the puck
