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PIT_PIT [208]
1 year ago
11

An empty bottle has a mass of 35.00 grams. When filled with water, it has a mass of 98.44 grams. Of the same bottle is filled wi

th a different fluid, the mass is 89.22 grams. What is the specific gravity of this other fluid
Physics
1 answer:
sveticcg [70]1 year ago
5 0

Answer:

Specific gravity of other fluid = .854 (Approx)

Explanation:

Given:

Mass of water = 35 g

Mass of filled bottle with water = 98.44 g

Mass of filled bottle with fluid = 89.22 g

Computation:

Mass of water = 98.44g - 35g = 63.44g

Density of water = 1000 g/L

Volume of bottle = 63.44/1000 = 0.06344L

Mass of other liquid = 89.22g - 35g = 54.22g

Density of other liquid = 54.22g/0.06344L = 854.665826 g/L

Water has a specific gravity = 1

So ,  specific gravity of other fluid

1000 / 854.665826 = 1 / specific gravity of other fluid

Specific gravity of other fluid = .854 (Approx)

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Calculate the time taken by the light to pass through a nucleus of diameter 1.56 10 -16 m. (speed of light is 3 10 8 m/s)
slega [8]

Answer:

5.2x10^-25

Explanation:

Time=(1.56x 10^-16)÷(3x10^8)

4 0
1 year ago
Why is it unwise to stir a pot of soup with a metal spoon?
emmasim [6.3K]

Answer:

Explanation:

As we stir the pot of soup by a metal spoon which is a conductor, it conducts the heat and starts heating after some time the temperature of the spoon rises and we are not able to hold the spoon and we get burns.

3 0
2 years ago
Read 2 more answers
For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo
Snezhnost [94]

Answer:

114.86%

Explanation:

In both cases, there is a vertical force equal to the sprinter's weight:

Fy = mg

When running in a circle, there is an additional centripetal force:

Fx = mv²/r

The net force is found with Pythagorean theorem:

F² = Fx² + Fy²

F² = (mv²/r)² + (mg)²

F² = m² ((v²/r)² + g²)

F = m √((v²/r)² + g²)

Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

5 0
1 year ago
A harmonic wave travels in the positive x direction at 6 m/s along a taught string. A fixed point on the string oscillates as a
Lapatulllka [165]

Answer:

Amplitude, A = 0.049 meters

Explanation:

Given that,

A harmonic wave travels in the positive x direction at 6 m/s along a taught string. A fixed point on the string oscillates as a function of time according to the equation :

y = 0.049 \cos(7t) .......(1)

The general equation of a wave is given by :

y=A\cos(\omega t) .......(2)

A is amplitude of wave

On comparing equation (1) and (2) we get :

A = 0.049 meters

So, the amplitude of the wave is 0.049 meters.

3 0
2 years ago
An engineer is designing a process for a new transistor. She uses a vacuum chamber to bombard a thin layer of silicon with ions
adelina 88 [10]

Answer:

E=5.7\times 10^{-3}\ V/m

Explanation:

Given that

m_p=5.18\times 10^{-26}\ kg

re= 46 cm

Vp= 180 m/s

We know that

E=\dfrac{\Delta V}{r}

\Delta V=\dfrac{1}{4}\dfrac{m_pv_p^2}{e}

So

E=\dfrac{1}{4}\dfrac{m_pv_p^2}{e.r_e}

Now by putting the all given values in the questions

E=\dfrac{1}{4}\times \dfrac{5.18\times 10^{-26}\times 180^2}{1.6\times 10^{-19}\times 0.46}

E=5.7\times 10^{-3}\ V/m

So the average electric field is E=5.7\times 10^{-3}\ V/m.

6 0
1 year ago
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