Answer:
It models conduction because the painter represents a charged object and the paint represents electrons that are transferred through contact.
Explanation:
Conduction phenomenon of charging is the process of charging in which two bodies are made in contact with each other so that charges are transferred due to potential difference of two bodies.
here we know that when hands are shake then it will have paint on it. so here due to hand shake the hands are in contact with charge particles and due to contact the electrons are transferred to the hand.
Now here we need to assume that charge of paint must be opposite that of the charge on the hand because only due to opposite charge attraction the paint must be transferred to the hand
SO here correct answer will be
It models conduction because the painter represents a charged object and the paint represents electrons that are transferred through contact.
Answer:
a=
Explanation:
The net force,
of the box is expressed as a product of acceleration and mass hence
where m is mass and a is acceleration
Making a the subject, a= 
From the attached sketch,
∑
where
is frictional force and
is horizontal angle
Substituting ∑
as
in the equation where we made a the subject
a= 
Since we’re given the value of F as 240N,
as 41.5N,
as
and mass m as 30kg
a= 
We are going to rewrite each number:
(4.48E-8) = 0.0000000448
(5.2E-4) = 0.00052
We observe that when multiplying, the exponent will be on the order of 10 ^ -11
Doing the multiplication we have:
(4.48E-8) * (5.2E-4) = 2.3296E-11
Rewriting:
(4.48E-8) * (5.2E-4) = 2.33E-11
Answer:
2.33E-11
9.8 ms^-2 is acceleration
Answer:
A. 261.6 hz.
B. 0.656 m.
Explanation:
A.
When yhe tube is open at one end and closed at the other,
F1 = V/4*L
Where,
F1 = fundamental frequency
V = velocity
L = length of the tube
When the tube is open at both ends,
F'1 = V/2*L
Where
F'1 = the new fundamental frequency
Therefore,
V/2*L x V/4*L
F'1 = 2 * F1
= 2 * 130.8
= 261.6 hz.
B.
F1 = V/4*L
Or
F'1 = V/2*L
Given:
V = 343 m/s
F1 = 130.8
L = 343/(4 * 130.8)
= 0.656 m.